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USPshnik [31]
4 years ago
14

(+30) + (+43)

84 + + 21" align="absmiddle" class="latex-formula">
​
Mathematics
1 answer:
zimovet [89]4 years ago
6 0

Answer:

1. 73

2.-63

Step-by-step explanation:

1. 30+43=73

2. -84+21= 21-84=-63

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What are these answers?
Shalnov [3]
#1 would be 45 degrees because you divide 360 by 8.
4 0
3 years ago
If you raise your workers salary be a scale factor of 9/5 and their salary is now $14.80 what was it before?​
asambeis [7]

Answer:

8

Step-by-step explanation:

4 0
3 years ago
Please help I only got 20 minutes to answer!!!!!!!!!
Digiron [165]

Answer:

r=c/2π

3/2π

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6 0
3 years ago
State if the triangles are similar. If so, how do you know they are similar and complete the similarity statement. Triangle LKJ≈
Llana [10]

Answer: C) similar, SAS similarity, triangle LQR

==============================================

Explanation:

The vertical angles KLJ and QLR are congruent. This forms the "A" in "SAS". The angles in question are between the marked sides.

KL = 18 is twice that of QL = 9, or put another way, KL/QL = 18/9 = 2. The ratio of the sides is 2. Also, JL/RL = 16/8 = 2 is the same ratio. Because both pairs of sides have the same ratio, the sides are in proportion. This helps form the two "S" letters of "SAS".

The original triangle has LKJ mentioned at the top. Note the order as its important. We start with L and move to K, so LK is the first segment mentioned. LK = 18 pairs up with LQ = 9, meaning that LQ must be the first segment mentioned of the answer triangle. Therefore LQR is the correct letter sequence if we start with point L. Writing QLR is not correct because Q is the first letter here but Q does not pair up with L.

4 0
3 years ago
In a random sample of fivefive microwave​ ovens, the mean repair cost was ​$75.0075.00 and the standard deviation was ​$13.0013.
Radda [10]
<h2>Answer with explanation:</h2>

As per given , we have

Sample size : n= 5

Degree pf freedom = : df= 5-1=4

\mu=\$75.00

\sigma=\$13.00

Significance level for 90% confidence = \alpha=1-0.90=0.1

Using t-value table , t-critical value for 90% confidence:

t_{\alpha/2, df}=t_{0.05, 4}=2.132.

Margin of error of \mu: E=t_{\alpha/2}\dfrac{\sigma}{\sqrt{n}}\\\\(2.132)\dfrac{13}{\sqrt{5}}=12.3949720129\approx12.39

Interpretation : The repair cost will be within $12.39 of the real population mean value \mu 90% of the time.

7 0
4 years ago
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