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Zigmanuir [339]
3 years ago
8

Which expression is equivalent to 3(6m)+m 3 6 m + m ?

Mathematics
1 answer:
svetlana [45]3 years ago
6 0

Answer:

some Equivalent expressions to 3(6m)+m is;

18m+m

6(3m)+m

2(9m)+m

19m

Step-by-step explanation:

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The number Of households with VCRs in 1990 was about 87.5% of the number with VCRs in 1993. About how many households had VCRs i
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I think you answer is 
63/87.5=.72 
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The constraints of a problem are listed below. What are the vertices of the feasible region?
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Consider quadrilateral LMNO. If quadrilateral LMNO is a parallelogram, what must the measure of angle LMN be? m∠LMN = °
koban [17]
The correct answer is 105 
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4 years ago
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can someone please help and explain to me on how to do this geometry question please?! Thank youuuuu!!! ❤
qaws [65]
There are 13 angles.
We know that m\angle4=112 and m\angle12=105 (11 angles)

1.

m\angle2+m\angle3+m\angle4=180\qquad\qquad\text{linear angles}\\\\m\angle3+m\angle3+m\angle4=180\qquad\qquad m\angle2=m\angle3\\\\2m\angle3+m\angle4=180\\\\2m\angle3+112=180\\\\2m\angle3=180-112\\\\2m\angle3=68\quad|:2\\\\\boxed{m\angle3=34=m\angle2}

(9 angles)

2.

m\angle3+m\angle12+m\angle11=180\qquad\qquad\text{triangle}\\\\34+105+m\angle11=180\\\\139+m\angle11=180\\\\m\angle11=180-139\\\\\boxed{m\angle11=41}

(8 angles)

3.

m\angle12+m\angle13=180\qquad\qquad\text{linear angles}\\\\105+m\angle13=180\\\\m\angle13=180-105\\\\\boxed{m\angle 13=75}

(7 angles)

4.

m\angle1+m\angle2+m\angle13=180\qquad\qquad\text{triangle}\\\\m\angle1+34+75=180\\\\m\angle1+109=180\\\\m\angle1=180-109\\\\\boxed{m\angle1=71}

(6 angles)

5.

m\angle9=m\angle11\qquad\qquad\text{vertical angles}\\\\\boxed{m\angle9=41}

(5 angles)

6.

m\angle10+m\angle11=180\qquad\qquad\text{linear angles}\\\\m\angle10+41=180\\\\m\angle10=180-41\\\\\boxed{m\angle10=139}

(4 angles)

7. a||b\text{ and } c||d so we have a parallelogram.

m\angle4+m\angle5=180\qquad\text{consecutive angles are supplementary}\\\\112+m\angle5=180\\\\m\angle5=180-112\\\\\boxed{m\angle5=68}

(3 angles)

m\angle8=m\angle5\qquad\qquad\text{opposite angels are congruent}\\\\\boxed{m\angle8=68}

(2 angles)

8.

m\angle7+m\angle8+m\angle9=180\qquad\qquad\text{triangle}\\\\m\angle7+68+41=180\\\\m\angle7+109=180\\\\m\angle7=180-109\\\\\boxed{m\angle7=71}

(1 angle)

9.

m\angle1+m\angle5+m\angle6=180\qquad\qquad\text{triangle}\\\\71+68+m\angle6=180\\\\139+m\angle6=180\\\\m\angle6=180-139\\\\\boxed{m\angle6=41}

6 0
3 years ago
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