Answer:
80
Step-by-step explanation:
thank you so much for the points, have a great day.
If x^2+bx+16 has at least one real root, then the equation x^2+bx+16=0 has at least one solution. The discriminant of a quadratic equation is b^2-4ac and it determines the nature of the roots. If the discriminant is zero, there is exactly one distinct real root. If the discriminant is positive, there are exactly two roots. The discriminant of <span>x^2+bx+16=0 is b^2-4(1)(16). The inequality here gives the values of b where the discriminant will be positive or zero:
b^2-4(1)(16) ≥ 0
</span><span>b^2-64 ≥ 0
(b+8)(b-8) </span><span>≥ 0
The answer is that all possible values of b are in the interval (-inf, -8]∪[8,inf) because those are the intervals where </span>(b+8)(b-8) is positive.
<span><span>23/40=0.575
Here you go</span></span>
Answer:

Step-by-step explanation:
You could change the equation to this: 
*This is the exact same as 
You can continue to break this down until you get:

*This too = 
With this new equation, you can cancel out the common term: 
You come up with my answer.
<em>Hope this helps!!</em>
Shift 5 in along the positive g(x) axis due to the + 5