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2 years ago

Help please! Could you put an explanation as well?

Mathematics

1 answer:

dusya [7]2 years ago

4 0

Answer:

y = 2x

Step-by-step explanation:

you multiply the x by 2 to get the y.

i don't know if this helps

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PLEASE HELP FAST WILL GIVE ALOT OF POINTS! Determine the distance between

Julli [10]

X-Axis > Positive, 6 Units
Y-Axia > Negative, 2 Units

To get from point A to point A' you need to move 6 units right (positive) and 2 units down (negative)

5 0

3 years ago

Read 2 more answers

HELP!!!!!!!!!!!!!!! please show your work, look at the picture

Margarita [4]

Answer:

B= 2y(3)/7x(8)

C= 12/ x(3) y(3)

D= The same because nothing else can be done with it

(parnthaces) are exponents

6 0

2 years ago

A person invests 7000 dollars in a bank. The bank pays 5.5% interest compounded

kotykmax [81]

The time required to get a total amount of $13,200.00 with compounded interest on a principal of $7,000.00 at an interest rate of 5.5% per year and compounded 12 times per year is 11.559 years. (about 11 years 7 months)

Answer:

t = 11.559 years

<h3>Compound Interest </h3>

Given Data

Principal P= $7000

Rate r= 5.5%

Final Amount A = $13200

Time t = ??

(about 11 years 7 months)

Calculation Steps:

First, convert R as a percent to r as a decimal

r = R/100

r = 5.5/100

r = 0.055 per year,

Then, solve the equation for t

t = ln(A/P) / n[ln(1 + r/n)]

t = ln(13,200.00/7,000.00) / ( 12 × [ln(1 + 0.055/12)] )

t = ln(13,200.00/7,000.00) / ( 12 × [ln(1 + 0.0045833333333333)] )

t = 11.559 years

Learn more about compound interest here:

brainly.com/question/24924853

6 0

1 year ago

How do you solve this?

kherson [118]

Interest equals principle (the amount that you had to begin with) times the rate (the rate if interest) times the time (usually in years)

3 0

2 years ago

An SRS of 350 high school seniors gained an average of x¯=21 points in their second attempt at the SAT Mathematics exam. Assume

Lynna [10]

Answer:

a) $21-2.58\frac{52}{\sqrt{350}}=13.83$

$21+2.58\frac{52}{\sqrt{350}}=28.17$

So on this case the 99% confidence interval would be given by (13.83;28.17)

b) $ME=2.58\frac{52}{\sqrt{350}}=7.17$

c) $ME=2.58\frac{52}{\sqrt{100}}=13.42$

d) D. Decreasing the sample size increases the margin of error, provided the confidence level and population standard deviation remain the same.

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

Part a

$\bar X=21$ represent the sample mean

$\mu$ population mean (variable of interest)

$\sigma=52$ represent the population standard deviation

n=350 represent the sample size

99% confidence interval

The confidence interval for the mean is given by the following formula:

$\bar X \pm z_{\alpha/2}\frac{\sigma}{\sqrt{n}}$ (1)

Since the Confidence is 0.99 or 99%, the value of $\alpha=0.01$ and $\alpha/2 =0.005$ , and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-NORM.INV(0.005,0,1)".And we see that $z_{\alpha/2}=2.58$

Now we have everything in order to replace into formula (1):

$21-2.58\frac{52}{\sqrt{350}}=13.83$

$21+2.58\frac{52}{\sqrt{350}}=28.17$

So on this case the 99% confidence interval would be given by (13.83;28.17)

Part b

The margin of error is given by:

$ME=2.58\frac{52}{\sqrt{350}}=7.17$

Part c

The margin of error is given by:

$ME=2.58\frac{52}{\sqrt{100}}=13.42$

Part d

As we can see when we reduce the sample size we increase the margin of error so the best option for this case is:

D. Decreasing the sample size increases the margin of error, provided the confidence level and population standard deviation remain the same.

6 0

2 years ago