3 years ago

Find the area of the sector of the circle with central angle of 225° and radius of 5 cm. Round to the nearest hundredth.

Mathematics

2 answers:

zubka84 [21]3 years ago

4 0

Ask me your other questions.i hope it was helpful

julsineya [31]3 years ago

3 0

The Area of Sector = 49.0873852187 thus 49.06 cm² the answer is C.

You might be interested in

Which color is the line that represents an equivalent ratio? How can you tell by looking at the lines?

slamgirl [31]

Answer:

Step-by-step explanation:

What that question from shawty im in CFS

6 0

3 years ago

I got no clue how to do this.

melisa1 [442]

Answer:

Step-by-step explanation:

Just to keep the computer happy by not having to figure out rounding answers that involve square roots and other problem numbers. I've chosen numbers that should work out evenly. And you should be able to draw the trapezoid.

Givens

H = 14

a = 23

b = 25

Area = 336

Formula

Area = (a + b)*h/2

Solution

Area = (23 + 25)*14/2

Area = 48 * 7

Area = 336

Note if a + b = 48 any values for a and b will work.

8 0

4 years ago

A builder mixes one part of cement with four parts of sand to make mortar if he uses 100 pounds of sand how much is cement?

fenix001 [56]

Answer:

Step-by-step explanation:

one part of 4 parts = 1/4

100 divided by 4 = 25

8 0

3 years ago

The drug Valium is eliminated from the bloodstream exponentially with a half-life of 36 hours. Suppose that a patient receives a

iogann1982 [59]

A = 75(1/2) ^ (24/36)

75 (1/2) ^ (2/3)

A = 47.2470 mg after 1 day.

-------------

35% of 75 is 26.25 mg, so

26.25 = 75(1/2) ^ (24/?)

26.25^(x/24) = 75 ((.5)

24root(26.25^x) = 37.5

Ignore this second part I don't know how to do. part a is correct.

5 0

3 years ago

Read 2 more answers

Given: x - 6 1/3≤ 1 1/2 Choose the solution set. a. {x | x ∈ R, x ≤ 7 5/6} b. {x | x ∈ R, x ≤ 7 2/5} c. {x | x ∈ R, x ≤ 5 1/6}

bija089 [108]

$x-6\frac{1}3\leq1\frac{1}2$

Add 6 1/3 to each side.

$x\leq1\frac{1}2+6\frac{1}3$

To add together the 1/2 and the 1/3, change them to a common denominator.

$x\leq1\frac{3}6+6\frac{2}6$

$x\leq7\frac{5}6$

$\boxed{\{\ x\ |\ x\in\mathbb{R},\ x\leq7\frac{5}6\}}$

4 0

3 years ago