Answer:
26.64%
Explanation:
Common stocks outstanding (C) = 80 million
Preffered stock outstanding (P) = 60 million
Number of bonds (B) = 50,000
Cost of common stock (Cc) = $20 per share
Cost of Preffered stock (Cp) = $10 per share
Cost of bond (Cb) = 105% of par
Weight of preferred stock :
(P * Cp) / [(P*Cp) + (C*Cc) + (B * Cb * par value)]
(60mill * $10) / [(60mill * $10) + (80mill * $20) + (50000 * 1.05 * 1000)]
600mill / (600 mill + 1600mill + 52.5mill)
600,000,000 / 2252500000
= 0.2663706
= 26.64%
When three possibilities are equally likely and have payoffs of $3, $6, and $9. Then the expected value will be $6.
<u>What is Expected Value? </u>
Expected value refers to when you play the game it will tell you the probability or winning chance and amount to win.
Hence, in the above questions, there are equally likely possibilities.
So, in this case, the probability for each possibility is 1/3.
We can calculate the expected value (EV) as:
EV=((1/3) x $3) + ((1/3) x $6) + ((1/3) x $9)
=1 + 2 + 3
=$6
Therefore, the expected value will be $6 when three possibilities are equally likely and have payoffs of $3, $6, and $9.
You can learn more about expected value at brainly.com/question/24305645
#SPJ4
Answer:
d. $15,000 is allocated to A; $10,000 is allocated to B
Explanation:
Activity C will not carry and suspended losses as it was profitable, the net of 25,000 will be distributed among the lossing activites:
60,000+ 40,000 = 100,000 loss
activity A weight 60%
activity B weight 40%
net loss: 25,000
activity A 25,000 x 60% = 15,000
activity B 25,000 x 40% = 10,000
