Question

Samuel found the difference of polynomials {15x^2+11y^2+8x}-{7x^2+5y^2+2x}=_x^2+6y^2+6x

Answer 1

Answer:

A = 8

Step-by-step explanation:

Given : Samuel found the difference of two polynomial $15x^2+11y^2+8x\\\\ 7x^2+5y^2+2x\\\\ \text{as}\ Ax^2+6y^2+6x$

We have to find the value of missing coefficient A in the result so obtained.

Consider

$15x^2+11y^2+8x-\left(7x^2+5y^2+2x\right)$

We first open parentheses as

$-\left(7x^2+5y^2+2x\right)=-\left(7x^2\right)-\left(5y^2\right)-\left(2x\right)$

Apply plus - minus rule, $+\left(-a\right)=-a$

$=-7x^2-5y^2-2x$

We get,

$=15x^2+11y^2+8x-7x^2-5y^2-2x$

Grouping like terms, we have,

$=15x^2-7x^2+8x-2x+11y^2-5y^2$

Simplify, we get,

$=8x^2+6x+6y^2$

On comparing with Given result , we have A = 8

Answer 2

X^2*(15 -7) = 8x^2

The missing coefficient is 8.