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3 years ago

What is the x and y intercept for f(x)= 2/3-4

Mathematics

1 answer:

Oksanka [162]3 years ago

5 0

Answer:

there is no x intercept

the y intercept is -10/3

Step-by-step explanation:

f(x) = 2/3 -4

get a common denominator

f(x) =2/3 - 4*3/3

f(x) = 2/3 - 12/3

f(x) = -10/3

this is a line at y = -10/3

there is no x intercept

the y intercept is -10/3

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3 years ago

If QT is 9 and TP is 8 Find the length of the following: RP RT RS

anyanavicka [17]

Answer:

i. RP = 17

ii. RT = 15

iii. RS = 30

Step-by-step explanation:

Given that; QT = 9 and TP = 8.

From the diagram, join R to P. Thus RP = QP (radius of the circle)

RP = QT + TP

= 9 + 8

RP = 17

Applying Pythagoras theorem to triangle TRP;

RT = $\sqrt{(RP)^{2} - (TP)^{2} }$

= $\sqrt{17^{2} - 8^{2} }$

= $\sqrt{225}$

= 15

∴ RT = 15

But, RT = TS = 15.

So that;

RS = 15 + 15

= 30

RS = 30

Therefore; RP = 17, RT = 15 and RS = 30.

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3 years ago

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3 years ago

Which person has the highest hourly wage? How do you know?

Inga [223]

Answer:

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Step-by-step explanation:

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2 years ago

Evaluate the following double integral: xy dA D where the region D is the triangular region whose vertices are (0, 0), (0, 3), (

natulia [17]

Answer:

I= 84

Step-by-step explanation:

for

$I=\int\limits^{}_{} \int\limits^{}_D {x*y} \, dA = \int\limits^{}_{} \int\limits^{}_D {x*y} \, dx*dy$

since D is the rectangle such that 0<x<3 , 0<y<3

$I=\int\limits^{}_{} \int\limits^{}_D {x*y} \, dA = \int\limits^{3}_{0} \int\limits^{3}_{0} {x*y} \, dx*dy = \int\limits^{3}_{0} {x} \, dx\int\limits^{3}_{0} {y} \, dy = x^{2} /2*y^{2} /2 = (3^{2} /2 - 0^{2} /2)* (3^{2} /2 - 0^{2} /2) = 3^{4} /4 = 81/4$

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3 years ago