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viktelen [127]
3 years ago
15

P forword Q is true an and q is true, then p is true sometimes always or never

Mathematics
1 answer:
vichka [17]3 years ago
4 0

Answer:

  • <u><em>Sometimes.</em></u>

Explanation:

The statement is <em>P forward Q is true and q is true, then p is true sometimes always or never.</em>

<em />

That, written using logical symbology, is:

  • p → q,
  • q is true
  • then p is ?

p → q is known as a conditional statement.

When the conditional p → q is true and p is also verified to be true, you must conclude that q is (necessarily) true (else the conditional would be false).

That also means that if q is verified to be false (not true), p must necessarily be false (else the conditional would be false).

Nevertheless, the fact that q is true, does not permit to conclude whether p is true or false: p can be either true or false when you only know that q is true.

Then, you cannot tell that p is true always or never; some times it could be true and others false.

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Answer:

Question 1- 288.48

Step-by-step explanation:

depending on how they round your answer the number might look different.

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What is the answer for 7.5+2.3y-y
Alexxx [7]

Answer:

9.8

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7.5+2.3y-y

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3 years ago
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3 years ago
Read 2 more answers
Find the value of ‘k’ if one zero of p(x) = kx2<br> – 14 x + 8 is 6 times the other.
Finger [1]

Answer:

<u>k = 3</u>

Step-by-step explanation:

one zero of p(x) = kx²– 14 x + 8 is 6 times the other.

let the zeros are ⇒ a and 6a

the equation kx²– 14 x + 8

can be written as k ( x²/k– 14/k x + 8/k)

So, a * 6a = 8/k    ⇒ (1)

And a + 6a = 14/k ⇒ (2)

from (2)  k = 14/(a + 6a) = 14/(7a) = 2/a

∴ a = 2/k

Substitute at (1)

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24/k = 8

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<u>the value of k = 3</u>

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