11.424242
isolate the repeating part
11+0.424242
focus on the repeating part
0.42424242
how many places till it repeats again?
2
let's say it is x
x=0.42424242
multiply by 100
100x=42.424242
subtract them
100x-x=42.42424242-0.42424242
the infinite repeats cancel and we get
99x=42
divide by 99
![x=\frac{42}{99}](https://tex.z-dn.net/?f=x%3D%5Cfrac%7B42%7D%7B99%7D)
so
Answer:
x = 37
Joe Mama said to use to pythagorus theorem. Then u can sing super idol
60%
Working
£5:100%
£1:20%
£8:160%
So percentage increase is 60%
3x+1=2x+4+x
3x
3x+1=3x+4
-1 -1
3x=3x+3
-3x
x=3
i think that would be your anser
Answer:
It will take 60 seconds for the signs to light up at the same time again.
Step-by-step explanation:
Given:
One sign lights up every 10 seconds
One sign lights up every 12 seconds
They have just lit up at the same time.
To find in how many seconds will it take for the signs to light up at the same time again.
Solution:
In order to find the time in seconds will it take for the signs to light up at the same time again, we need to find the least common multiple of the the times for which the given signs light up.
The numbers are 10 and 12.
To find the LCM, we will list the multiples of each and check the least common multiple.
The multiples of 10 and 12 are :
![10\rightarrow 10,20,30,40,50,60,70](https://tex.z-dn.net/?f=10%5Crightarrow%2010%2C20%2C30%2C40%2C50%2C60%2C70)
![12\rightarrow 12,24,36,48,60](https://tex.z-dn.net/?f=12%5Crightarrow%2012%2C24%2C36%2C48%2C60)
thus, we can see that 60 is the least common multiple.
Thus, the signs will light up at the same time time after every 60 seconds.