For Question 1:
angle CAB, angle ABC, angle BCA
Question 2: angle BCD
Given:
The given quadratic polynomial is :
To find:
The quadratic polynomial whose zeroes are negatives of the zeroes of the given polynomial.
Solution:
We have,
Equate the polynomial with 0 to find the zeroes.
Splitting the middle term, we get
The zeroes of the given polynomial are -3 and 4.
The zeroes of a quadratic polynomial are negatives of the zeroes of the given polynomial. So, the zeroes of the required polynomial are 3 and -4.
A quadratic polynomial is defined as:
Therefore, the required polynomial is .
Okay, so first you draw a picture and let x be the distance from point D to the rest stop. Then the distance from point to the rest stop is 8 - x
You know that the length of the new trail is y + z, where y is the distance from Ancaster to the rest stop and z is the distance from Dundas to the rest stop.
Now by the Pythagorean theorem, y^2 = 4^2 + x^2 and z^2 = 6^2 + (8 - x) ^2
So take square roots of these, add them, and minimize.
Note: I am assuming the path is perfectly straight, otherwise this approach fails.
Answer:
..............
Step-by-step explanation:
Remember to do PEMDAS so your answer is not correct, since you multiplied before doing the parentheses/exponents.
Explanation:
3(3)^2- 5(4)
= 3(9) - 5(4)
= 27 - 20 = 7
