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Nikitich [7]
3 years ago
5

We all hate to bring change to a store. By using random numbers, we can eliminate the need for change and give the store and the

customer a fair deal. Suppose you buy something for 20 cents. If the store generated a random number using the cash register (call the random number R), what rule could they use to decide whether you should pay $1 or $0 for the item
Mathematics
1 answer:
Sunny_sXe [5.5K]3 years ago
6 0

Answer:

Round off to closest value.

Step-by-step explanation:

In order to remove the requirement for change, every time the client buys a product for $0.20 the random number that lies between 0 and 1 would be produced also the same would be rounded to the closest value i.e. 0 or 1. In the case when 0 arise so the customer would not have to pay any amount but if 1 arise so the customer have to pay $1. So this type of method would remove the requirement for a minor change

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Answer:

It is B

Step-by-step explanation:

I hope this helps!

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9000 dollars is placed in an account with an annual interest rate of 8%. How much will be in the account after 17 years, to the
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Answer:

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Step-by-step explanation:


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3 years ago
When simplified, the expression (x^1/8)(x^3/8) is 12. Which is a possible value of x?
Nata [24]

we have  

(x^{\frac{1}{8}})(x^{\frac{3}{8}})=12

we know that

(x^{\frac{1}{8}})(x^{\frac{3}{8}})=12\\ \\x^{(\frac{1}{8}+{\frac{3}{8}})}=12\\ \\x^{\frac{4}{8}}=12\\ \\x^{\frac{1}{2}}=12

Square both sides

x^{(\frac{1}{2})^{2}} =12^{2}

x^{\frac{2}{2}}=12^{2} \\\\x=144

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<u>the answer is the option C</u>

144

7 0
3 years ago
Read 2 more answers
Square root of root of 32 x to the cube power
UkoKoshka [18]
The square root of 32 is 5.65*3(cubed)is 16.95
7 0
4 years ago
I need help with this!!!!!
irakobra [83]

Answer:

A) 4(7+x)=64

B) 4x+7=64

Step-by-step explanation:

A

4(7+x)=64

*Disturabute 4 to (7+x)*

28+4x=64

*Subtract 28 on both sides*

4x=36

*Divide by 4*

x=9

**If you do a Check it works*

B

4x+7=64

*Subtract 7*

4x=57

*Divide by 4*

x=14.25

**If you do a Check this also works**

Hope This Helps!!!

3 0
3 years ago
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