Answer:
The probability that a child is born with this genetic trait is 0.03.
Step-by-step explanation:
The probability that a woman is a carrier of a particular genetic trait is,
P (W) = 0.15.
The probability that a man is a carrier of a particular genetic trait is,
P (M) = 0.20.
The two events are independent of each other, since the event of a woman being a carrier is not affected by the man being a carrier and vice-versa.
It is provided that this trait can only be inherited by a child if both parents are carriers.
Compute the probability that both parents are carriers of the trait as follows:
![P(W\cap M)=P(W)\times P(M)](https://tex.z-dn.net/?f=P%28W%5Ccap%20M%29%3DP%28W%29%5Ctimes%20P%28M%29)
![=0.15\times 0.20\\=0.03](https://tex.z-dn.net/?f=%3D0.15%5Ctimes%200.20%5C%5C%3D0.03)
Thus, the probability that a child is born with this genetic trait is 0.03.
Answer:
C:
Step-by-step explanation:
In the attached file
Yes that is correct need 20 words
8.25x= 15 so....
15/8.25=x so....
1.81~=x so....
To the nearest dollar it 2$/lb
Make a scatter plot based on the data given.