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Leno4ka [110]
2 years ago
9

Write a division problem whose quotient has its first digit in the hundreds place

Mathematics
1 answer:
Margaret [11]2 years ago
8 0
Quotient is another name for the answer to a division problem

the hundreds place is the 3rd number before the decimal, 9999999.0
                                                                                           ^this one

so you need to find a division problem that equals something between 100 and 999

1000 divided by 10 is a good one, the answer to that problem is 100, and 100 has its first digit in the hundreds place.
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Sebastian wants to create a right triangle with side lengths 14 inches, 48 inches, and 5
allochka39001 [22]

Answer: Choice A

\text{Yes, because } 14^2+48^2 \text{ is equal to } 50^2

=======================================================

Explanation:

The pythagorean theorem is a^2+b^2 = c^2

The value of c is always the longest side, aka hypotenuse.

The order of 'a' and b doesn't matter.

So a = 14, b = 48, c = 50

We have a^2+b^2 = 14^2+48^2 = 196+2304 = 2500

We also have c^2 = 50^2 = 2500

Both sides result in 2500 which proves that 14^2+48^2 = 50^2 is a true statement. Therefore, we do have a right triangle.

7 0
2 years ago
Round 0.866 to the nearest tenth​
Scilla [17]

To round 0.866 to the nearest tenth consider the hundredths' value of 0.866, which is 6 and equal or more than 5. Therefore, the tenths value of 0.866 increases by 1 to 9.

The answer is <u><em>0.9</em></u>

plz mark me as brainliest if this helped :)

4 0
3 years ago
Read 2 more answers
If 45% of a number , e is 180 , what is 95% of e​
Sergeeva-Olga [200]

Answer:

380

Step-by-step explanation:

Find 1% of e:

180 / 45 = 4

Find 95% of e:

4 * 95 = 380

3 0
2 years ago
which expression have a value of 16/81? check all that apply. (2/3)^4, (16/3)^4, (4/81)^2, and (4/9)^2
notka56 [123]

Use\ \left(\dfrac{a}{b}\right)^n=\dfrac{a^n}{b^n}\\\\\left(\dfrac{2}{3}\right)^4=\dfrac{2^4}{3^4}=\dfrac{16}{81}\ :)\\\\\left(\dfrac{16}{3}\right)^4=\dfrac{16^4}{3^4}=\dfrac{16^4}{81}\neq\dfrac{16}{81}\ :(\\\\\left(\dfrac{4}{81}\right)^2=\dfrac{4^2}{81^2}=\dfrac{16}{81^2}\neq\dfrac{16}{81}\ :(\\\\\left(\dfrac{4}{9}\right)^2=\dfrac{4^2}{9^2}=\dfrac{16}{81}\ :)

6 0
3 years ago
Read 2 more answers
Divide $2.50 in a ratio of 4:1
hram777 [196]

Step-by-step explanation:

4x + x = 2.5 \\  \\  \therefore \: 5x = 2.5 \\  \\  \therefore \: x =  \frac{2.5}{5}  = 0.5 \\  \\  \therefore \:  4x = 4 \times 0.5 = 2

Hence, 2.50 in the ratio 4 : 1 can be divided as 2 and 0.5

4 0
3 years ago
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