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3 years ago

5+7k>=-30 and -4k +4>20

Mathematics

1 answer:

Slav-nsk [51]3 years ago

7 0

Answer:

$\large\boxed{-5\leq k$

Step-by-step explanation:

$5+7k\geq-30\ \wedge\ -4k+4>20\\\\5+7k\geq-30\qquad\text{subtract 5 from both sides}\\7k\geq-35\qquad\text{divide both sides by 7}\\\boxed{k\geq-5}\\\\-4k+4>20\qquad\text{subtract 4 from both sides}\\-4k>16\qquad\text{change the signs}\\4k$

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After all markdowns and discounts, Charlene’s prom dress cost her $22 before tax. The dress was on a rack labeled “50% off lowes

goldfiish [28.3K]

Answer:

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Step-by-step explanation:

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3 years ago

Complete the equation of the line through (-6,-5)(−6,−5)(, minus, 6, comma, minus, 5, )and (-4,-4)(−4,−4)(, minus, 4, comma, min

alina1380 [7]

Answer:

$y=\frac{1}{2}x-2$

Step-by-step explanation:

We have been given two points on a line $(-6,-5)$ and $(-4,-4)$ . We are asked to write an equation passing through these points.

We will write our equation in slope-intercept form of equation $y=mx+b$ , where,

m = Slope of line,

b = Initial value or the y-intercept.

Let us find slope of given line using slope formula.

$m=\frac{y_2-y_1}{x_2-x_1}$

Let point $(-6,-5)=(x_1,y_1)$ and point $(-4,-4)=(x_2,y_2)$ .

$m=\frac{-4-(-5)}{-4-(-6)}$

$m=\frac{-4+5}{-4+6}$

$m=\frac{1}{2}$

Now, we will substitute $m=\frac{1}{2}$ and coordinates of point $(-6,-5)$ in slope-intercept form of equation as:

$-5=\frac{1}{2}*(-6)+b$

$-5=-3+b$

$-5+3=-3+3+b$

$-2=b$

Upon substituting $m=\frac{1}{2}$ and $b=-2$ in slope-intercept form of equation, we will get our required equation as:

$y=\frac{1}{2}x-2$

Therefore, our required equation would be $y=\frac{1}{2}x-2$ .

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2 years ago

Given that ∠ABC ≅ ∠DBE, which statement must be true?

Gala2k [10]

Line Segment AB<span> ≅ Line Segment DB </span>

6 0

3 years ago

Read 2 more answers

H(x) = x2<br> j(x) = 2x2-5<br> find h(x) - j(x)

yKpoI14uk [10]

Answer:

Step-by-step explanation:

h(x) - j(x) => $x^2-(2x^2-5)$

The negative sign out in front of the set of parenthesis changes the signs of everything inside the parenthesis, so now we have, without parenthesis:

$x^2-2x^2+5$ which simplifies down to

$-x^2+5$

4 0

2 years ago

What are the solutions of the quadratic equation (x + 3)(x +3) = 49? Ax = -2 and x = -16 Bx = 2 and x = -10 Cx = 4 and x = -10 D

Ivahew [28]

Answer:

4 and -10

Step-by-step explanation:

$\displaystyle (x + 3)(x +3) = 49 \\ x^2+3x+3x+9=49 \\ x^2 +6x+9=49 \\ x^2 + 6x + 9 - 49 = 0 \\x^2+6x-40=0 \\\\ \Delta=b^2-4ac \\ \Delta=6^2-4 \cdot 1 \cdot (-40) \\ \Delta=36+160 \\ \Delta=196 \\ \\ X_{1,2}=\frac{-b \pm \sqrt{\Delta} }{2a} \\ \\ X_1=\frac{-b+\sqrt{\Delta} }{2a} = \frac{-6+14}{2} = \frac{8}{2}=4 \\ \\ X_2=\frac{-b-\sqrt{\Delta} }{2a} = \frac{-6-14}{2}=\frac{-20}{2} = -10$

4 0

3 years ago

5+7k>=-30 and -4k +4>20​

5+7k>=-30 and -4k +4>20