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Alex Ar [27]
3 years ago
8

(r-s)2=(___)2-(___)rs+s2

Mathematics
1 answer:
nasty-shy [4]3 years ago
7 0
(r-s)² = r² - 2rs +s²
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What is the row echelon form of this matrix?
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The row echelon form of the matrix is presented as follows;

\begin{bmatrix}1 &-2  &-5  \\ 0& 1 &  -7\\ 0&0  &1  \\\end{bmatrix}

<h3>What is the row echelon form of a matrix?</h3>

The row echelon form of a matrix has the rows consisting entirely of zeros at the bottom, and the first entry of a row that is not entirely zero is a one.

The given matrix is presented as follows;

\begin{bmatrix}-3 &6  &15  \\ 2& -6 &  4\\ 1&0  &-1  \\\end{bmatrix}

The conditions of a matrix in the row echelon form are as follows;

  1. There are row having nonzero entries above the zero rows.
  2. The first nonzero entry in a nonzero row is a one.
  3. The location of the leading one in a nonzero row is to the left of the leading one in the next lower rows.

Dividing Row 1 by -3 gives:

\begin{bmatrix}1 &-2  &-5  \\ 2& -6 &  4\\ 1&0  &-1  \\\end{bmatrix}

Multiplying Row 1 by 2 and subtracting the result from Row 2 gives;

\begin{bmatrix}1 &-2  &-5  \\ 0& -2 &  14\\ 1&0  &-1  \\\end{bmatrix}

Subtracting Row 1 from Row 3 gives;

\begin{bmatrix}1 &-2  &-5  \\ 0& -2 &  14\\ 0&2  &4  \\\end{bmatrix}

Adding Row 2 to Row 3 gives;

\begin{bmatrix}1 &-2  &-5  \\ 0& -2 &  14\\ 0&0  &18  \\\end{bmatrix}

Dividing Row 2 by -2, and Row 3 by 18 gives;

\begin{bmatrix}1 &-2  &-5  \\ 0& 1 &  -7\\ 0&0  &1  \\\end{bmatrix}

The above matrix is in the row echelon form

Learn more about the row echelon form here:

brainly.com/question/14721322

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