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Shalnov [3]
3 years ago
5

Each of 6 samples has a different standard deviation. How many of the 6 samples could be from the same population?

Mathematics
2 answers:
DENIUS [597]3 years ago
8 0

Answer:6

Step-by-step explanation:

pav-90 [236]3 years ago
3 0
I would think 32 so yea....because (12/98=49<33>**+{45-63-12{45+58-28} =32
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The sum of three consecutive odd integers is 207. What are the​ integers?
nikdorinn [45]
Hey!

It says that it is the sum of 3 consecutive odd integers right?

So then we give these numbers some variables to work with like so...

x = 1st number
x + 2 = 2nd number
x + 4 = 3rd number

now set all of them equal to 207

x + x + 2 + x + 4 = 207
3x + 6 = 207
3x = 201
<u>x = 67</u><u />                     <u>x + 2 = 69</u><u />              <u /><u />   <u>x + 4 = 71
</u>
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4 0
3 years ago
1. Kylie wrote the expression below. (9 + k) x 5 What is the value of Kylie's expression for k= 4? A 65 B 41 C 29 D 28​
TEA [102]
Answer: A 65
Explanation: using PEMDAS you substitute 4 in for k and add 9+4 because it’s in parenthesis. Then you multiply the 13 you get from that by 5 and get 65.
5 0
3 years ago
Factor Quadratics
miv72 [106K]

Answer:

Step-by-step explanation:

x^2 - 14x + 45

(x - 9)(x - 5)

8 0
3 years ago
2/5 + r = 1 and 4/5 <br> What is r?
MariettaO [177]
Answer- r= 7\5 hope this helps!!
7 0
3 years ago
Given a+b+c=7 and a^2+b^2+c^2=25 Find (a+b) ^2+(a+c) ^2+(b+c) ^2
marissa [1.9K]

Answer:

26.

Step-by-step explanation:

(a + b)^2 + (a+ c)^2 + (b + c)^2 =   a^2 + b^2 - 2 ab + a^2 + c^2 - 2ac + b^2 + c^2 - 2bc

= 2( a^2 + b^2  + c^2 ) - 2( ab + ac + bc)

=<em>  </em><em>5</em>0 - 2(ab + ac + bc).............. (1).

(a + b + c)^2 = a^2 + ab + ac + ab + b^2 + bc + ac + bc + c^2

= a^2 + b^2 + c^2 + 2(ab + ac + bc)

= 25 + 2(ab + ac + bc)

But (a + b + c)^2 = 7^2 = 49. So:-

49 = 25 + 2(ab + ac + bc)

2(ab + ac + bc) = 49 - 25 = 24.

Substituting for this  in (1) above:

(a + b)^2 + (a + c)^2 + (b + c)^2 =  50 - 24 = 26 (answer).

8 0
3 years ago
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