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2 years ago

PLEASE HELP ASAP ILL GIVE 100 POINTS TO ANYONE THAT ANSWERS CORRECTLY

Mathematics

1 answer:

Inga [223]2 years ago

7 0

Answer:

1/5

Step-by-step explanation:

I think thats right idI dont knowk ahaha sorry if its not

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The equation 7.50(n+0.2)=189 can be used to model the number of books, n , maggie orders. How many books does maggie order?

Reptile [31]

N= number of books

7.50(n + 0.2)=189
multiply 7.50 by each term in parentheses

(7.50*n) + (7.50*0.2)= 189
7.50n + 1.5= 189
subtract both sides by 1.5
7.50n= 187.50
divide both sides by 7.50
n= 25

ANSWER: She ordered 25 books.

Hope this helps! :)

4 0

3 years ago

Please help me with the below question.

VMariaS [17]

By letting

$y = \displaystyle \sum_{n=0}^\infty c_n x^{n+r}$

we get derivatives

$y' = \displaystyle \sum_{n=0}^\infty (n+r) c_n x^{n+r-1}$

$y'' = \displaystyle \sum_{n=0}^\infty (n+r) (n+r-1) c_n x^{n+r-2}$

a) Substitute these into the differential equation. After a lot of simplification, the equation reduces to

$5r(r-1) c_0 x^{r-1} + \displaystyle \sum_{n=1}^\infty \bigg( (n+r+1) c_n + (n + r + 1) (5n + 5r + 1) c_{n+1} \bigg) x^{n+r} = 0$

Examine the lowest degree term $\left(x^{r-1}\right)$ , which gives rise to the indicial equation,

$5r (r - 1) + r = 0 \implies 5r^2 - 4r = r (5r - 4) = 0$

with roots at r = 0 and r = 4/5.

b) The recurrence for the coefficients $c_k$ is

$(k+r+1) c_k + (k + r + 1) (5k + 5r + 1) c_{k+1} = 0 \implies c_{k+1} = -\dfrac{c_k}{5k+5r+1}$

so that with r = 4/5, the coefficients are governed by

$c_{k+1} = -\dfrac{c_k}{5k+5} \implies \boxed{g(k) = -\dfrac1{5k+5}}$

c) Starting with $c_0=1$ , we find

$c_1 = -\dfrac{c_0}5 = -\dfrac15$

$c_2 = -\dfrac{c_1}{10} = \dfrac1{50}$

so that the first three terms of the solution are

$\displaystyle \sum_{n=0}^2 c_n x^{n + 4/5} = \boxed{x^{4/5} - \dfrac15 x^{9/5} + \frac1{50} x^{13/5}}$

4 0

2 years ago

Help me plssssssssssss

DiKsa [7]

9514 1404 393

Answer:

f^-1(x) = 4+∛((x-6)/5)

Step-by-step explanation:

To find the inverse function, solve ...

x = f(y)

then write the answer in functional form.

$\displaystyle x=f(y)\\\\x=5(y-4)^3+6\\\\x-6=5(y-4)^3\\\\\frac{x-6}{5}=(y-4)^3\\\\\sqrt[3]{\frac{x-6}{5}}=y-4\\\\y=4+\sqrt[3]{\frac{x-6}{5}}\\\\\boxed{f^{-1}(x)=4+\sqrt[3]{\frac{x-6}{5}}}$