The probability that atleast one ticket labeled 2-6 is drawn is 0.94
Numbered ticket = {1, 2, 3, 4, 5, 6, 7, 8, 9, 10}
Number of draws = 4
Required picks = {2, 3, 4, 5, 6}
<u>Recall</u><u> </u><u>:</u>
- <em>Probability</em><em> </em><em>=</em><em> </em><em>required</em><em> </em><em>outcome</em><em> </em><em>/</em><em> </em><em>Total possible</em><em> </em><em>outcomes</em><em> </em>
<u>Probability</u><u> </u><u>of</u><u> </u><u>choosing a</u><u> </u><u>required</u><u> </u><u>ticket</u><u> </u><u>:</u>
Therefore, the probability that none of the required tickets is chosen :
- (1/2 × 1/2 × 1/2 × 1/2) = 1/16
The probability that atleasr one ticket labeled 2-6 is drawn is :
1 - P(none is chosen) = 1 - 1/16 = 15/16 = 0.9375
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