Question

A doll and a toy t-rex cost $33 together. If the t-rex toy costs $9.50 more than the doll, how much did the doll cost?

Answer 1

Answer:

Doll cost = $11.75.

Step-by-step explanation:

Given  :A doll and a toy t-rex cost $33 together. If the t-rex toy costs $9.50 more than the doll.

To find :   how much did the doll cost.

Solution : We have given

A doll and a toy t-rex cost $33 together.

Let the Doll cost = x .

According to question .

t-rex toy costs $9.50 more than the doll.

T-rex cost = $9.50+ x .

Then, A doll and a toy t-rex cost $33 together.

Doll cost + T oy t-rex cost =  $33

Plugging the values

x +  $9.50+ x  =$33 .

2x + $9.50 =$33 .

On subtracting both sides by $9.50

2x =33 - 9.50

2x = 23.5.

On dividing both sides b y 2

x = $11.75

Doll cost  =$11.75

Toy Cost = 9.50 +11.75.

Toy Cost = $21.25

Therefore, Doll cost = $11.75.

Answer 2

Answer:

The cost of the doll is $11.75

Step-by-step explanation:

Let

x ----> the cost of the doll

y ----> the cost of the toy t-rex

we know that

$x+y=33$ -----> equation A

$y=x+9.50$ ----> equation B

substitute equation B in equation A and solve for x

$x+(x+9.50)=33\\2x+9.50=33\\2x=33-9.50\\2x=23.50\\x=\ 11.75$

therefore

The cost of the doll is $11.75