Ask question

Ask question

All categories

3 years ago

6

The odds of winning a game of horse in basketball is 3 to 5 against your opponent. what is the probability that you win the game

1 answer:

Marat540 [252]3 years ago

7 0

To find your probability of winning, you will convert the fraction 3/5 to a percent.

You can do this by dividing 3 and 5 to get 0.6 and then 60%, or you can create an equivalent fraction with a denominator of 100.

<u>3 </u> <u>60</u>
5 = 100

60%

You might be interested in

Can anybody help me plz

Alja [10]

You do 3.14×diameter... the diameter in this case is 10

4 0

3 years ago

Read 2 more answers

May y’all help me with this

m_a_m_a [10]

Answer:

y=3x+2

Step-by-step explanation:

y is going up by 3 as x goes up by 1 so slope=3/1=3.

We can use this pattern to determine what will happen at x=0 (the y-intercept). 5-3=2 so the y-intercept is 2.

Slope-intercept form is y=mx+b where m is slope and b is y-intercept.

The equation is y=3x+2.

6 0

3 years ago

SOLVE ONLY C AND D PLS

KengaRu [80]

C) 6x ( 3 - 2x^2)
d) 6x^2 (2x + 1)

3 0

2 years ago

During the first hour of operation the farm stand owner sold 15% of the apples he had. On the second hour he sold 20% of the rem

liraira [26]

Answer:

3.825 kg apples.

Step-by-step explanation:

Let x kg be the amount of apples stand owner had initially.

We have been given that during the first hour of operation the farm stand owner sold 15% of the apples he had. Then the amount of sold apples will be:

$\text{The amount of sold apples during 1st hour}=\frac{15}{100}x=0.15x$

$\text{The amount of remaining apples after 1st hour}=x-0.15x$

$\text{The amount of remaining apples after 1st hour}=0.85x$

On the second hour he sold 20% of the remaining apples. So the amount of sold apples on the second hour will be 20% of 0.85x.

$\text{The amount of sold apples during 2nd hour}=0.85x*\frac{20}{100}$

$\text{The amount of sold apples during 2nd hour}=0.85x\times 0.20$

$\text{The amount of sold apples during 2nd hour}=0.17x$

During the second hour 25.5 kg of apples were sold, so we can set up an equation as:

$25.5=0.17x$

$\frac{25.5}{0.17}=\frac{0.17x}{0.17}$

$150=x$

So, stand owner had initially 150 kg of apples.

$\text{The amount of remaining apples after 2nd hour}=0.85x-0.17x$

$\text{The amount of remaining apples after 2nd hour}=0.68x$

On the third hour he sold 25% of the remaining apples. So the amount of sold apples on the 3rd hour will be 25% of 0.68x

$\text{The amount of sold apples during 3rd hour}=0.68x*\frac{25}{100}$

$\text{The amount of sold apples during 3rd hour}=0.68x*0.25$

$\text{The amount of sold apples during 3rd hour}=0.17x$

$\text{The amount of remaining apples after 3rd hour}=0.68x-0.17x$

$\text{The amount of remaining apples after 3rd hour}=0.51x$

As remaining apples were sold 5% more each following hour.

$\text{The amount of sold apples during 4th hour}=0.51x*\frac{5}{100}$

$\text{The amount of sold apples during 4th hour}=0.51x*0.05$

$\text{The amount of sold apples during 4th hour}=0.0255x$

Let us substitute x=150 into above equation we will get,

$\text{The amount of sold apples during 4th hour}=0.0255*150$

$\text{The amount of sold apples during 4th hour}=3.825$

Therefore, 3.825 kg of apples were sold during the 4th hour.

7 0

3 years ago

This is related to my grade

spin [16.1K]

It depends on the weight of the assignment in the class

8 0

3 years ago