Ask question

Ask question

All categories

2 years ago

7

A chemist has 200mL of a 10% sucrose solution. She adds x mL of a 40% sucrose solution. The chemist needs the concentration of t

he final mixture to be 30% how many milliliters of the 40% solution should she add to the 10% solution to get this concentration ?

1 answer:

LekaFEV [45]2 years ago

6 0

Answer:

566

Step-by-step explanation:

You might be interested in

X/2-1=3 what is X PLEASE HELPPPPPPPPPPP

valentina_108 [34]

Answer:

4

Step-by-step explanation:

3 0

2 years ago

Read 2 more answers

-10+8x=70 Anyone have the answer for these <br><br><br><br> 142+x x+62

Naddik [55]

Answer:

Step-by-step explanation:

U need to think

7 0

2 years ago

Multi step equations <br> 4-5x=29

Gemiola [76]

Answer: x = -5

Step-by-step explanation:

1) subtract 4 from both sides (-5x = 25)

2) divide -5 from both sides (x = -5)

Then you have the answer!

6 0

3 years ago

Find the partial fraction decomposition of the rational expression with prime quadratic factors in the denominator

SpyIntel [72]

$\dfrac{5x^4-7x^3-12x^2+6x+21}{(x-3)(x^2-2)^2}=\dfrac{a_1}{x-3}+\dfrac{a_2x+a_3}{x^2-2}+\dfrac{a_4x+a_5}{(x^2-2)^2}$
$\implies 5x^4-7x^3-12x^2+6x+21=a_1(x^2-2)^2+(a_2x+a_3)(x-3)(x^2-2)+(a_4x+a_5)(x-3)$

When $x=3$ , you're left with

$147=49a_1\implies a_1=\dfrac{147}{49}=3$

When $x=\sqrt2$ or $x=-\sqrt2$ , you're left with

$\begin{cases}17-8\sqrt2=(\sqrt2a_4+a_5)(\sqrt2-3)&\text{for }x=\sqrt2\\17+8\sqrt2=(-\sqrt2a_4+a_5)(-\sqrt2-3)\end{cases}\implies\begin{cases}-5+\sqrt2=\sqrt2a_4+a_5\\-5-\sqrt2=-\sqrt2a_4+a_5\end{cases}$

Adding the two equations together gives $-10=2a_5$ , or $a_5=-5$ . Subtracting them gives $2\sqrt2=2\sqrt2a_4$ , $a_4=1$ .

Now, you have

$5x^4-7x^3-12x^2+6x+21=3(x^2-2)^2+(a_2x+a_3)(x-3)(x^2-2)+(x-5)(x-3)$
$5x^4-7x^3-12x^2+6x+21=3x^4-11x^2-8x+27+(a_2x+a_3)(x-3)(x^2-2)$
$2x^4-7x^3-x^2+14x-6=(a_2x+a_3)(x-3)(x^2-2)$

By just examining the leading and lagging (first and last) terms that would be obtained by expanding the right side, and matching these with the terms on the left side, you would see that $a_2x^4=2x^4$ and $a_3(-3)(-2)=6a_3=-6$ . These alone tell you that you must have $a_2=2$ and $a_3=-1$ .

So the partial fraction decomposition is

$\dfrac3{x-3}+\dfrac{2x-1}{x^2-2}+\dfrac{x-5}{(x^2-2)^2}$

7 0

3 years ago

There were 64 basketball games during the ncaa tournament. 16 of those games were decided by 3 points or less. What percentage o

liubo4ka [24]

Answer:

25%

Step-by-step explanation:

Form the fraction 16/64, evaluate it (obtaining 1/4) and multiply this result by 100%. This results in 25%.

25 % of the games played were decided by 3 points or less

5 0

3 years ago