If you're finding slope, the answer is 5/3
Problem
For a quadratic equation function that models the height above ground of a projectile, how do you determine the maximum height, y, and time, x , when the projectile reaches the ground
Solution
We know that the x coordinate of a quadratic function is given by:
Vx= -b/2a
And the y coordinate correspond to the maximum value of y.
Then the best options are C and D but the best option is:
D) The maximum height is a y coordinate of the vertex of the quadratic function, which occurs when x = -b/2a
The projectile reaches the ground when the height is zero. The time when this occurs is the x-intercept of the zero of the function that is farthest to the right.
Answer:
See below description.
Step-by-step explanation:
The function 
has the following characteristics:
- Factors:
- Zeros/roots: x=0, x=-1, amd x=4
- Positive leading coefficient
- Graph starts down and curves up through -1 on the x-axis and back down to cross through 0. It curves back up again through 4 and finished off heading into positive infinity.
- Its graph is the shape of a sideways S.
- It has a relative maximum at 1.128 and relative minimum value of -13.128
Answer:
6
Step-by-step explanation:
