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yanalaym [24]
3 years ago
8

Y= 9x -9 y= 9 substitution method

Mathematics
1 answer:
Aneli [31]3 years ago
3 0
You would plug in the y=9 into the first equation and then have the expression 9=9x-9
. After going through the first steps of solving an expression you would get 18=9x. X=2. Then you would plug in the x value into the first expression to get y=9.
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3. Consider the sequence,-8, -5, -2, 1, ...
Naddik [55]

Answer:

a) a_n=3\,n-11

b) a_{20}=49

c) term number 17 is the one that gives a value of 40

Step-by-step explanation:

a)

The sequence seems to be arithmetic, and with common difference d = 3.

Notice that when you add 3 units to the first term (-80, you get :

-8 + 3 = -5

and then -5 + 3 = -2 which is the third term.

Then, we can use the general form for the nth term of an arithmetic sequence to find its simplified form:

a_n=a_1+(n-1)\,d

That in our case would give:

a_n=-8+(n-1)\,(3)\\a_n=-8+3\,n-3\\a_n=3n-11

b)

Therefore, the term number 20 can be calculated from it:

a_{20}=3\,(20)-11=60-11=49

c) in order to find which term renders 20, we use the general form we found in step a):

a_n=3\,n-11\\40=3\,n-11\\40+11=3\,n\\51=3\,n\\n=\frac{51}{3} =17

so term number 17 is the one that renders a value of 40

5 0
3 years ago
The vertex of the function y= 32x-4x^2
mafiozo [28]

I'm very sure the answer would be (4, 64)

7 0
3 years ago
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What is the slope of the line y=2x+5?​
sweet [91]
Answer:

The slope is 2

Explanation:

The equation is written in y=mx+b
M would always be the slope and b the y intercept

Hope this helps!!
4 0
3 years ago
Read 2 more answers
Find the quotient of 675 and 5
Stells [14]
The quotient of 675 and 5 would be 135.
675/5=135
Hope this helps!
8 0
3 years ago
Mr Todd buys 7 drinks at 48p each and 8 drinks at 52p each. What is the total cost of the 15 drinks?
Lesechka [4]

Answer:

80p

if you are adding 4p every time you add a drink you will be adding 7  drinks therefore you have to do (7x4p) this will equal 28p then you have to add 28p to 52p

Hope this helps

6 0
3 years ago
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