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Tcecarenko [31]
3 years ago
14

When Sam gave Clarissa 105 chocolates, Clarissa had 5 times as many chocolates as Sam. They had 504 chocolates altogether. How m

any more chocolates did Clarissa have at first?
Mathematics
1 answer:
nataly862011 [7]3 years ago
6 0

Answer:

315 chocolate

Step-by-step explanation:

Let Sam's chocolate be S

Let Clariss's chocolate be C

When Sam gave Clarissa 105 chocolates, Clarissa had 5 times as many chocolates as Sam.

This can be written as:

C = 5S

The sum of their chocolate is 504 i.e

S + C = 504

Now, let us determine the chocolate of Clarissa after receiving 105 chocolate from Sam. This can be obtained as follow:

S + C = 504

But: C = 5S

S + 5S = 504

6S = 504

Divide both side by 6

S = 504/6

S = 84.

C = 5S = 5 x 84 = 420

Therefore, Clarissa have 420 chocolate after receiving 105 chocolate from Sam.

Now, to know the amount of chocolate that Clarissa has at first, we simply subtract 105 from the present amount that Clarissa have. This is illustrated below:

Amount of chocolate that Clarissa has a first = 420 – 105 = 315

Therefore, Clarissa had 315 chocolate at first.

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Can anyone help me set up a system of equations for these problems??
statuscvo [17]

Answer:

L = the length of the field

W = the width of the field

The First Question:

The system is: L - 12 = w

                         2L + 2W = 76

Plug in L - 12 for W and you will get

2L + 2L - 24 = 76

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2 years ago
A FEW MATH QUESTIONS ! PLEASE EXPLAIN ANSWERS ! (:
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answers

1) 70

2) 3,840

3) 24

4) 72


<u>Explanation</u>

Q1

The surface area of a cone is given by;

S.A = 2Πrl + Πr²

Where r is the radius of the base and l is the lateral height.

Πr² = area of the base = 20 in²

2Πrl = Area of the lateral surface

         = 2.5 × 20

          = 50

Area of the cone = 50 + 20

                            = 70 in²

Q2

The sides of the Pythagorean triangle with legs of 12 and 16.

The 3rd side will be;

c = √(12² + 16²)

  = √400 = 20

Volume = 12 × 16 × 20

              = 3,840

Q3

The volume of a cone is given by;

volume = 1/3 Π r² h

This shows that the volume of a cone is a third the volume of the cylinder.

∴ Volume of the cylinder = 12 × 3

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Q4

The volume of any regular figure is;

Volume = base area × height

When the dimensions area usually 3. Let these dimensions be x, y and z.

∴ volume  = x × y × z = 9

  Doubling the dimensions;

Volume = 2x × 2y × 2z = 2 × 2 × 2 × 9

             = 8 × xyz = 8 × 9

             = 72 ft²



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