Answer:
h = 61.25 m
Step-by-step explanation:
It is given that,
The initial velocity of the ball, v = 60 m/s
It is thrown from a height of 5 feet, 
We need to find the maximum height it reaches. The height reached by the projectile as a function of time t is given by :

Putting all the values,
.....(1)
For maximum height, put

Put t = 1.875 in equation (1)

So, the maximum height reached by the ball is 61.25 m.
Answer:
If they are not parallel they will cross.
The angle types that are still congruent are the angles that are the same size.
Step-by-step explanation:
Parallel lines never cross but non parallel lines cross.
<h2><u><em>
Could I please have BRAINLIEST?</em></u></h2>
Answer:
13:3
Step-by-step explanation:
A=x B=y
first; x= 360+y
later;x= 216+y
A:B
216+y: 1/2y = 6: 1
216+y/y÷2 =6/1
216+y = 3y
y = 108
first; x =360+y
360 +108
468
A:B = 468:108
13:3
Firstly, we will select three corner points
A=(2,3)
B=(6,8)
C=(7,4)
we are given
the transformation with the rule (x, y)→(x, −y)
y--->-y
so, it is reflected about x-axis
so, we will multiply y-value by -1
we get new points as
A=(2,-3)
B=(6,-8)
C=(7,-4)
now, we can locate these points and draw graph
we get
Answer:
Step-by-step explanation:
√2x(7 + √2x)
7√2x + √2x ·√2x
7√2x + 2x
or
2x + 7√2x
A is the answer