All categories

4 years ago

Use Picture to find x

Mathematics

1 answer:

-Dominant- [34]4 years ago

5 0

To find the hypotenuse, we can use the pythagorean theorem.

The answer is 52.33 (rounded to the nearest hundredth).

Hope this helps!

You might be interested in

78% of students in the 7th grade

irina1246 [14]

Answer:

Step-by-step explanation:

percentage Students

78%-------------- -273

100%-------------- ---X

(100x273)/78 = 350 students in class so

how many did not pass?

350-273 = 77 students not pass

6 0

3 years ago

Read 2 more answers

Sheldon earned $245.00 on Monday He is paid $35.00 per hour Whe

fredd [130]

Answer: 3:45PM

Step-by-step explanation: 245 / 35 = 7. 7 hours after 8:45AM is 3:45PM.

8 0

3 years ago

Read 2 more answers

Ms hall buys 8 plants for his garden each plant cost $5 the next day he buys a rose bush thst also cost $5 how much more do the

enyata [817]

They cost $35 more than the rose bush.

5 0

3 years ago

Jada, Diego, and Elena each use the same spinner that has four (not necessarily equal sized) sections marked A, B, C, and D.

natta225 [31]

Answer:

diego

Step-by-step explanation:

diego is right cause the spinner has four sides and he spun 5 times

8 0

3 years ago

Find the measures of the three angles, in radians, of the triangle with the given vertices: d(1,1,1), e(1,−5,2), and f(−2,2,7).

Oduvanchick [21]

Consider triangle DEF with vertices D(1,1,1), E(1,-5,2) and F(-2,2,7).

1. Find

$\overrightarrow{DE}=(1-1,-5-1,2-1)=(0,-6,1),\\ \\\overrightarrow{DF}=(-2-1,2-1,7-1)=(-3,1,6).$

Then

$\cos \angle D=\dfrac{0\cdot (-3)+(-6)\cdot 1+1\cdot 6}{\sqrt{0^2+(-6)^2+1^2}\cdot \sqrt{(-3)^2+1^2+6^2}}=\dfrac{0}{\sqrt{37} \cdot \sqrt{46} }=0.$

2. Find

$\overrightarrow{ED}=(1-1,1-(-5),1-2)=(0,6,-1),\\ \\\overrightarrow{EF}=(-2-1,2-(-5),7-2)=(-3,7,5).$

Then

$\cos \angle E=\dfrac{0\cdot (-2)+6\cdot 7+(-1)\cdot 5}{\sqrt{0^2+6^2+(-1)^2}\cdot \sqrt{(-3)^2+7^2+5^2}}=\dfrac{37}{\sqrt{37} \cdot \sqrt{83} }=\sqrt{\dfrac{37}{83}}.$

3. Find

$\overrightarrow{FE}=(1-(-2),-5-2,2-7)=(3,-7,-5),\\ \\\overrightarrow{FD}=(1-(-2),1-2,1-7)=(3,-1,-6).$

Then

$\cos \angle F=\dfrac{3\cdot 3+(-7)\cdot (-1)+(-5)\cdot (-6)}{\sqrt{3^2+(-7)^2+(-5)^2}\cdot \sqrt{3^2+(-1)^2+(-6)^2}}=\dfrac{46}{\sqrt{83} \cdot \sqrt{46} }=\sqrt{\dfrac{46}{83}}.$

$\angle E=\arccos0=\dfrac{\pi}{2},\\ \\
\angle D=\arccos\letf(\sqrt{\dfrac{37}{83}}\right)\approx 0.27\pi,\\ \\
\angle F=\arccos\letf(\sqrt{\dfrac{46}{83}}\right)\approx 0.23\pi.$

3 0

3 years ago