Please Answer This, the question is on the picture. it needs to be a fraction

Oatmeal is packaged in a cylindrical container, as shown in the diagram. The diameter of the container is 13 centimeters and its

aivan3 [116]

Hi there!

FACTS :

The formula for the volume of a cylinder is : V = $\pi$ × r² × h

STEPS TO ANSWER:

You have the diameter of the cylinder, which is 13cm.

In order to have the radius of the cylinder to put in our formula, you'll need to divide the diameter by 2 because the diameter is two times the radius:

13 ÷ 2 = 6.5

Now that you have the radius (6.5) and the height (24cm) of the cylinder, you can put these information in the formula and calculate de volume :

V = $\pi$ × r² × h

V = $\pi$ × 6.5² × 24

V = $\pi$ × 42.25 × 24

V = $\pi$ × 1,014

V = 3,185.574950......

Since you need to round your answer to the nearest tenth, which means that you will have only one decimal, the volume of the cylindrical container would be about 3,185.6cm³.

There you go! I really hope this helped, if there's anything just let me know! :)

5 0

3 years ago

Im stuck on this question i need help

Korolek [52]

I think it’s one half 1/2

4 0

3 years ago

Please help. Look at screenshot

Citrus2011 [14]

Answer:

a.

Increasing:

x < 0

x > 2

Decreasing:

0 < x < 2

b.

-1 < x < 2

x > 2

c.

x < -1

Step-by-step explanation:

a.

Function is increasing when it is going up as we go rightward

Function is decreasing when it is going down as we go rightward

We can see that as we move up (from negative infinity) until x = 0, the function is increasing. Also, as we go right from x = 2 towards positive infinity, the function is going up (increasing).

So,

Increasing:

x < 0

x > 2

The function is going down, or decreasing, at the in-between points of increasing, that is from 0 to 2, so that would be:

Decreasing:

0 < x < 2

b.

When we want where the function is greater than 0, we basically want the intervals at which the function is ABOVE the x-axis [ f(x) > 0 ].

Looking at the graph, it is

from -1 to 2 (x axis)

and 2 to positive infinity

We can write:

-1 < x < 2

x > 2

c.

Now we want when the function is less than 0, that is basically saying when the function is BELOW the x-axis.

This will be the other intervals than the ones we mentioned above in part (b).

Looking at the graph, we see that the graph is below the x-axis when it is less than -1, so we can write:

x < -1

4 0

3 years ago

How do I write the exponent expression below in numbers

Irina-Kira [14]

Answer:

(3^6)/2

Step-by-step explanation:

make sure everything as the numerator is in parenthesis

4 0

3 years ago

Which of the following equations might have the graph shown?

jonny [76]

we will select each options and then we verify it

(a)

we can see that circle is in first quadrant

so, it's center coordinates must be positive

both h and k should be positive

Here , h=2 but k=-3

so, this is FALSE

(B)

we can see that circle is in first quadrant

so, it's center coordinates must be positive

both h and k should be positive

Here , h=3 and k=4

so, this is TRUE

(C)

we can see that circle is in first quadrant

so, it's center coordinates must be positive

both h and k should be positive

Here , h=-3 and k=-4

so, this is FALSE

(D)

we can see that circle is in first quadrant

so, it's center coordinates must be positive

both h and k should be positive

Here , h=5 and k=5

so, this is TRUE

(E)

we can see that circle is in first quadrant

so, it's center coordinates must be positive

both h and k should be positive

Here , we have all terms positive

so, h and k must be negative here

so, this is FALSE

(E)

we can see that circle is in first quadrant

so, it's center coordinates must be positive

both h and k should be positive

Here , we have -4x and -6y

which will have h and k positive

so, this is TRUE

8 0

3 years ago