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3 years ago

What is the value of (8 – 3)!? A. 336 B. 40,314 C. 5 D. 120

Mathematics

2 answers:

vredina [299]3 years ago

8 0

C. 8-3=5 you do what is inside the parentheses first

Tom [10]3 years ago

5 0

Anything that is inside the perenthasis are just like a regular math problem, so your answer should be:
C. 5

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An arithmetic sequence has the following properties:

WINSTONCH [101]

Answer:

Easy peasy

Step-by-step explanation:

7+(n-1)5

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3 years ago

Consider the function f(x) = x^3 - 7x^2 - 2x + 14

mars1129 [50]

Answer:

There are 3 zeros, which are:

$x=7,\:x=-\sqrt{2},\:x=\sqrt{2}$

Step-by-step explanation:

Given the function

$f\left(x\right)\:=\:x^3\:-\:7x^2\:-\:2x\:+\:14$

To get the zeros of $f(x)$ , set $y$ or $f(x) =0$

$0=x^3-7x^2-2x+14$

$x^3\:-\:7x^2\:-\:2x\:+\:14=\left(x-7\right)\left(x+\sqrt{2}\right)\left(x-\sqrt{2}\right)$

$\left(x-7\right)\left(x+\sqrt{2}\right)\left(x-\sqrt{2}\right)=0$

Using the zero factor principle:

$\mathrm{ \:If}\:ab=0\:\mathrm{then}\:a=0\:\mathrm{or}\:b=0\:\left(\mathrm{or\:both}\:a=0\:\mathrm{and}\:b=0\right)$

$x-7=0\quad \mathrm{or}\quad \:x+\sqrt{2}=0\quad \mathrm{or}\quad \:x-\sqrt{2}=0$

solving

$x-7=0$

$x=7$

$x+\sqrt{2}=0$

$x=-\sqrt{2}$

$x-\sqrt{2}=0$

$x=\sqrt{2}$

Therefore, there are 3 zeros, which are:

$x=7,\:x=-\sqrt{2},\:x=\sqrt{2}$

8 0

3 years ago

3(6p-1)=11p-45 heeelp

aksik [14]

Answer:

p = -6

Step-by-step explanation:

pls give brainliest if im right

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2 years ago

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3 years ago

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Sides, or lengths and widths

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