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3 years ago

Can someone please help me

Mathematics

1 answer:

leva [86]3 years ago

8 0

The number line represents the fractions

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marcus buys 10 containes of yogurt. Each container of yogurt is 2/3 cup. how many cups of yogurt does marcus buy

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6 2/3 cups

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3 years ago

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Dawson is covering a large cylinder with brown paper. He'll need to find the volume of the cylinder in order to determine how mu

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3 years ago

20% of x is 11. What is x?

ipn [44]

Answer:

Step-by-step explanation:

20% is the same as 1/5, so we can multiply 11 by 5:

11*5=55

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3 years ago

A study of the relationship between age and various visual functions (such as acuity and depth perception) reported the followin

Mila [183]

Answer:

Σxi =56.61

Σxi²=196.23

Step-by-step explanation:

X be the random variable represents area of scleral lamina (mm2) from human optic nerve heads

Σxi can be obtain by adding all x values

Σxi=2.79+2.53+2.78+3.79+2.33+2.72+3.88+4.15+3.79+4.43+3.47+4.47+2.5+3.61+2.77+3.53+3.07=56.61

Σxi =56.61

Σxi² can be obtained by squaring x values and then adding them.

Σxi²=2.79²+2.53²+2.78²+3.79²+2.33²+2.72²+3.88²+4.15²+3.79²+4.43²+3.47²+4.47²+2.5²+3.61²+2.77²+3.53²+3.07²=196.233

Σxi²=196.23

8 0

3 years ago

An investment of $8,000 earns interest at an annual rate of 7% compounded continuously. Complete parts (A) and (B) below. Click

Sergeeva-Olga [200]

Answer:

A. $\mathtt{\dfrac{dA}{dt}|_{t=2}=644.15}$

B. $\mathtt{\dfrac{dA}{dt}|_{t = 5.79}= 839.86 }$

Step-by-step explanation:

Given that:

An investment of Amount = $8000

earns at an annual rate of interest = 7% = 0.07 compounded continuously

The objective is to :

A) Find the instantaneous rate of change of the amount in the account after 2 year(s).

we all know that:

$A = Pe^{rt}$

where;

$A = (8000) \ e ^{0.7t}$

The instantaneous rate of change = $\dfrac{dA}{dt}$

$\dfrac{dA}{dt} = \dfrac{d}{dt}(8000 \ e ^{0.07t} )$

$= 8000 \dfrac{d}{dt}e^{0.07 \ t}$

$\dfrac{dA}{dt}= 8000 (0.07)e^{0.07 \ t}$

$\dfrac{dA}{dt}= 560 e^{0.07 \ t}$

At t = 2 years; the instantaneous rate of change is:

$\dfrac{dA}{dt}|_{t=2}= 560 e^{0.07 \times 2}$

$\mathtt{\dfrac{dA}{dt}|_{t=2}=644.15}$

(B) Find the instantaneous rate of change of the amount in the account at the time the amount is equal to $12,000.

Here the amount = 12000

$12000 = (8000)e^{0.07 \ t}$

$\dfrac{12000 }{8000}= e^{0.07 \ t}$

$1.5= e^{0.07 \ t}$

㏑(1.5) = 0.07 t

0.405465 = 0.07 t

t = 0.405465 /0.07

t = 5.79

$\dfrac{dA}{dt}= 560 e^{0.07 \ t}$

At t = 5.79

$\dfrac{dA}{dt}|_{t = 5.79}= 560 e^{0.07 \times 5.79}$

$\mathtt{\dfrac{dA}{dt}|_{t = 5.79}= 839.86 }$

7 0

3 years ago