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34kurt
3 years ago
15

The weight of an object on Earth varies directly as the weight of the same object on the moon. A 300 pound object on Earth would

weigh 48 pounds on the moon. How much would a 75 pound object on Earth weigh on the moon? (Type your number answer. NO LABELS) *
Mathematics
1 answer:
slava [35]3 years ago
7 0

Answer: 12 pounds.

Step-by-step explanation:

To solve this question, we'll use the direct proportion which is.

y = kx

Where,

y = weight on moon = 48 pounds

x = weight on Earth = 300 pounds

k = Unknown

y = kx

48 = 300k

k = 48/300

k = 0.16

The weight that a 75 pound object on Earth would weigh on the moon will be:

y = kx

where,

y = weight on moon = Unknown

k = 0.16

x = weight on Earth = 75 pounds

y = kx

y= 0.16 × 75

y = 12 pounds

The weight on the moon will be 12 pounds.

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x is greater than 8

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2 years ago
If (x + 2) is a factor of x3 − 6x2 + kx + 10, k =
ch4aika [34]

Answer:

The value of k is -11

Step-by-step explanation:

If (x+2) is a factor of x3 − 6x2 + kx + 10:

Then,

f(x)=x3 − 6x2 + kx + 10

f(-2)=0

f(-2)=(-2)³-6(-2)²+k(-2)+10=0

f(-2)= -8-6(4)-2k+10=0

f(-2)= -8-24-2k+10=0

Solve the like terms:

f(-2)=-2k-22=0

f(-2)=-2k=0+22

-2k=22

k=22/-2

k=-11

Hence the value of k is -11....

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Step-by-step explanation:

4 0
3 years ago
Peggy had three times as many quarters as nickels. She had $1.60 in all. How many nickels and how many quarters did she have?
Nonamiya [84]
0.05n + 0.25q = 1.60
q = 3n

0.05n + 0.25(3n) = 160
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8 0
3 years ago
Read 2 more answers
4/5 ÷ 7/6 + 2/7 ∙2 1/5
Aleksandr [31]
<h2>The value of \dfrac{4}{5} ÷ \dfrac{7}{6} + \dfrac{2}{7}.2\dfrac{1}{5} =\dfrac{8}{7}</h2>

Step-by-step explanation:

We have,

\dfrac{4}{5} ÷ \dfrac{7}{6} + \dfrac{2}{7}.2\dfrac{1}{5}

To find, the value of \dfrac{4}{5} ÷ \dfrac{7}{6} + \dfrac{2}{7}.2\dfrac{1}{5} = ?

∴ \dfrac{4}{5} ÷ \dfrac{7}{6} + \dfrac{2}{7}.2\dfrac{1}{5}

=\dfrac{4}{5}\times \dfrac{6}{7} +\dfrac{2}{7}.\dfrac{8}{5}

=\dfrac{24}{35} +\dfrac{16}{35}

Taking LCM of denominator, we get

=\dfrac{24+16}{35}

=\dfrac{40}{35}

Dividing numerator and denominator by 5, we get

=\dfrac{8}{7}

∴ The value of \dfrac{4}{5} ÷ \dfrac{7}{6} + \dfrac{2}{7}.2\dfrac{1}{5} =\dfrac{8}{7}

Hence, the value of \dfrac{4}{5} ÷ \dfrac{7}{6} + \dfrac{2}{7}.2\dfrac{1}{5} is equal to \dfrac{8}{7} .

4 0
3 years ago
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