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34kurt
3 years ago
15

The weight of an object on Earth varies directly as the weight of the same object on the moon. A 300 pound object on Earth would

weigh 48 pounds on the moon. How much would a 75 pound object on Earth weigh on the moon? (Type your number answer. NO LABELS) *
Mathematics
1 answer:
slava [35]3 years ago
7 0

Answer: 12 pounds.

Step-by-step explanation:

To solve this question, we'll use the direct proportion which is.

y = kx

Where,

y = weight on moon = 48 pounds

x = weight on Earth = 300 pounds

k = Unknown

y = kx

48 = 300k

k = 48/300

k = 0.16

The weight that a 75 pound object on Earth would weigh on the moon will be:

y = kx

where,

y = weight on moon = Unknown

k = 0.16

x = weight on Earth = 75 pounds

y = kx

y= 0.16 × 75

y = 12 pounds

The weight on the moon will be 12 pounds.

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Using confidence interval concepts, it is found that:

a) The point estimate is the sample mean.

b) The confidence interval is: \overline{x} \pm T\frac{s}{n}

c) If $1411 is between the bounds of the interval yes, otherwise no.

--------------

  • At item a, it asks to provide a point estimate for the population mean, which is the sample mean \overline{x}

--------------

Item b:

  • In the spreadsheet, it is possible to find the <em>standard deviation for the sample</em>, thus, the t-distribution is used.
  • The confidence interval will be given by:

\overline{x} \pm T\frac{s}{n}

In which:

  • \overline{x} is the sample mean.
  • T is the critical value, from the t-distribution, with a two-tailed area of \frac{1 - 0.95}{2} = 0.025 and n-1 degrees of freedom.
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  • n is the sample size.

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Item c:

We have to check if 1411 is between \overline{x} - T\frac{s}{n} and \overline{x} +T\frac{s}{n}.

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A similar problem is given at brainly.com/question/24232455

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