Question

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Answer 1

After solving the system of equations,  x= -3 and y=6

Step-by-step explanation:

We need to solve the following system of equations by substitution.

$-3x + y = 15\,\,\,(1)\\-8x-7y = -18\,\,\,(2)$

Finding value of y from equation(1) and substituting it in equation(2)

$y=15+3x\\substituting\,\,in\,\,equation(2)\\-8x-7(15+3x)=-18\\Solving:\\-8x-105-21x=-18\\-8x-21x=-18+105\\-29x=87\\x=\frac{87}{-29}\\x=-3$

The value of x is x=-3

Now, Finding value of x from eq(1) and substituting in equation(2)

$-3x=15-y\\x=\frac{15-y}{-3}\\Substituting\,\,in\,\,equation(2)\\-8(\frac{15-y}{-3})-7y=-18\\\frac{120-8y}{3}-7y=-18\\\frac{120-8y-7y*3}{3}=-18\\\frac{120-8y-21y}{3}=-18\\\frac{120-29y}{3}=-18\\120-29y=-18*3\\120-29y=-54\\-29y=-54-120\\-29y=-174\\y=\frac{-174}{-29}\\y=6$

So, Value of y is y=6

After solving the system of equations,  x= -3 and y=6

Keywords: system of equations

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