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pickupchik [31]
4 years ago
5

Anwser both of them please

Mathematics
1 answer:
eimsori [14]4 years ago
4 0
The rectangle on the right is 81 and the rectangle on the left is 24. I don't really know about the second one sorry, but I hope this helped.
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Combine the like terms to create a equivalent expression 9t - 3t +4
avanturin [10]

Answer:

6t+4

Step-by-step explanation:

9t-3t+4=6t+4

Combine the like terms 9t and -3t

Hope this helps!

4 0
3 years ago
Read 2 more answers
Mid-West Publishing Company publishes college textbooks. The company operates an 800 telephone number whereby potential adopters
s344n2d4d5 [400]

The various answers to the question are:

  • To answer 90% of calls instantly, the organization needs four extension lines.
  • The average number of extension lines that will be busy is Four
  • For the existing phone system with two extension lines, 34.25 % of calls get a busy signal.

<h3>How many extension lines should be used if the company wants to handle 90% of the calls immediately?</h3>

a)

A number of extension lines needed to accommodate $90 in calls immediately:

Use the calculation for busy k servers.

$$P_{j}=\frac{\frac{\left(\frac{\lambda}{\mu}\right)^{j}}{j !}}{\sum_{i=0}^{k} \frac{\left(\frac{\lambda}{\mu}\right)^{t}}{i !}}$$

The probability that 2 servers are busy:

The likelihood that 2 servers will be busy may be calculated using the formula below.

P_{2}=\frac{\frac{\left(\frac{20}{12}\right)^{2}}{2 !}}{\sum_{i=0}^{2} \frac{\left(\frac{20}{12}\right)^{t}}{i !}}$$\approx 0.3425$

Hence, two lines are insufficient.

The probability that 3 servers are busy:

Assuming 3 lines, the likelihood that 3 servers are busy may be calculated using the formula below.

P_{j}=\frac{\frac{\left(\frac{\lambda}{\mu}\right)^{j}}{j !}}{\sum_{i=0}^{2} \frac{\left(\frac{\lambda}{\mu}\right)^{i}}{i !}}$ \\\\$P_{3}=\frac{\frac{\left(\frac{20}{12}\right)^{3}}{3 !}}{\sum_{i=0}^{3} \frac{\left(\frac{20}{12}\right)^{1}}{i !}}$$\approx 0.1598$

Thus, three lines are insufficient.

The probability that 4 servers are busy:

Assuming 4 lines, the likelihood that 4 of 4 servers are busy may be calculated using the formula below.

P_{j}=\frac{\frac{\left(\frac{\lambda}{\mu}\right)^{j}}{j !}}{\sum_{i=0}^{k} \frac{\left(\frac{\lambda}{\mu}\right)^{t}}{i !}}$ \\\\$P_{4}=\frac{\frac{\left(\frac{20}{12}\right)^{4}}{4 !}}{\sum_{i=0}^{4} \frac{\left(\frac{20}{12}\right)^{7}}{i !}}$

Generally, the equation for is  mathematically given as

To answer 90% of calls instantly, the organization needs four extension lines.

b)

The probability that a call will receive a busy signal if four extensions lines are used is,

P_{4}=\frac{\left(\frac{20}{12}\right)^{4}}{\sum_{i=0}^{4} \frac{\left(\frac{20}{12}\right)^{1}}{i !}} $\approx 0.0624$

Therefore, the average number of extension lines that will be busy is Four

c)

In conclusion, the Percentage of busy calls for a phone system with two extensions:

The likelihood that 2 servers will be busy may be calculated using the formula below.

P_{j}=\frac{\left(\frac{\lambda}{\mu}\right)^{j}}{j !}$$\\\\$P_{2}=\frac{\left(\frac{20}{12}\right)^{2}}{\sum_{i=0}^{2 !} \frac{\left(\frac{20}{12}\right)^{t}}{i !}}$$\approx 0.3425$

For the existing phone system with two extension lines, 34.25 % of calls get a busy signal.

Read more about signal

brainly.com/question/14699772

#SPJ1

3 0
2 years ago
The time it takes me to wash the dishes is uniformly distributed between 5 minutes and 12 minutes. What is the probability that
GalinKa [24]

Answer:

0.2857

Step-by-step explanation:

We define the time it takes to do these dishes to be uniformly distributed between the time 5 minutes and 12 minutes.

a = 5 minutes

b = 12 minutes

Probability of tonight's dish washing being between 6 and 8 minutes

P(6<X<8)

= 8-6/b-a

= 2/12-5

= 2/7

= 0.2857

The probability it will be better 6 and 8 minutes is therefore 0.2857

5 0
3 years ago
Find the square root of the fraction 64/100
kirill [66]
The simplified answer is 4/5
3 0
3 years ago
Read 2 more answers
What is 1/8 divided by 2
slavikrds [6]
When dividing 1/8 by 2
we have to first take the reciprocal of 2 
reciprocal is when the numerator and denominator are exchanged
2 when written as a fraction is \frac{2}{1}
we need to find the reciprocal of \frac{2}{1} which is \frac{1}{2}
then 
\frac{1}{2} of \frac{1}{8}
when 'of' function is used it means to multiply the 2 fractions 
when multiplying fractions multiply the numerators by numerators and multiply denominators by denominators 
is \frac{1}{2} * \frac{1}{8} =  \frac{1}{16}
answer is \frac{1}{16}

4 0
4 years ago
Read 2 more answers
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