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3 years ago

What is the scale factor on a graph

1 answer:

4 0

Answer: The scale factor of a dilation is the factor by which each linear measure of the figure (for example, a side length) is multiplied.

Step-by-step explanation:

A dilation can be described in coordinate notation as (x,y)→(2x,2y)

You might be interested in

Rewrite 8^6 • 8^4 in the form 8^n

Ede4ka [16]

Answer:

8^10

Step-by-step explanation:

Keep it as in power form. Note that the base is the same (8).

When the case is that the base is the same:

If multiplying, add the powers together.

If dividing, subtract the powers.

8^6 * 8^4 = 8^(6 + 4) = 8^10

8^10 is your answer.

5 0

3 years ago

Read 2 more answers

PLZ HELP ASAP INSCRIBED QUADRILATERALS

svp [43]

For an inscribed quadrilateral, opposite angles add up to 180 degrees. In this case, if we are looking for the measure of angle D, we can use the fact that angles I & D add up to 180 degrees. Since angle I = 117:
117 + D = 180
D = 63 degrees

8 0

3 years ago

16⎯⎯⎯⎯√ – (14 + 2) : 2

ollegr [7]

Answer:

Our square root calculator estimates the square root of any positive number you want. Just enter the chosen number and read the results.

Step-by-step explanation:

8 0

2 years ago

Topic: The Quadratic Formula

Finger [1]

Answer:

Step-by-step explanation:

The quadratic formula for a equation of form

ax²+bx + c = 0 is

$x= \frac{-b +- \sqrt{b^2-4ac} }{2a}$

For the first equation,

x²+3x-4=0,

we can match that up with the form

ax²+bx + c = 0

to get that

ax² = x²

divide both sides by x²

a=1

3x = bx

divide both sides by x

3 = b

-4 = c

. We can match this up because no constant multiplied by x could equal x² and no constant multiplied by another constant could equal x, so corresponding terms must match up.

Plugging our values into the equation, we get

$x= \frac{-3 +- \sqrt{3^2-4(1)(-4)} }{2(1)} \\= \frac{-3+-\sqrt{25} }{2} \\ = \frac{-3+-5}{2} \\= -8/2 or 2/2\\= -4 or 1$

as our possible solutions

Plugging our values back into the equation, x²+3x-4=0, we see that both f(-4) and f(1) are equal to 0. Therefore, this has 2 real solutions.

Next, we have

x²+3x+4=0

Matching coefficients up, we can see that a = 1, b=3, and c=4. The quadratic equation is thus

$x= \frac{-3 +- \sqrt{3^2-4(1)(4)} }{2(1)}\\= \frac{-3 +- \sqrt{9-16} }{2}\\= \frac{-3 +- \sqrt{-7} }{2}\\$

Because √-7 is not a real number, this has no real solutions. However,

(-3 + √-7)/2 and (-3 - √-7)/2 are both possible complex solutions, so this has two complex solutions

Finally, for

4x² + 1= 4x,

we can start by subtracting 4x from both sides to maintain the desired form, resulting in

4x²-4x+1=0

Then, a=4, b=-4, and c=1, making our equation

$x=\frac{-(-4) +- \sqrt{(-4)^2-4(4)(1)} }{2(4)} \\= \frac{4+-\sqrt{16-16} }{8} \\= \frac{4+-0}{8} \\= 1/2$

Plugging 1/2 into 4x²+1=4x, this works as the only solution. This equation has one real solution

7 0

3 years ago

Help!<br>What is the answer to this question?<br><br>

Nadya [2.5K]

Answer:

Step-by-step explanation:

8 0

3 years ago