Question

Find the surface area of a right triangle prism with legs measuring 3 and 4 and a height of 10.

Answer 1

Since we have a rectangle triangle, then we can find the other side of the triangle using the Pythagorean theorem.
 We have then:
 $L = \sqrt{3^2+4^2}$
 $L = \sqrt{9+16}$
 $L = \sqrt{25}$
 $L = 5$
 Then the surface area is given by the sum of the areas.
 Triangle of the base and the top:
 $A1 = (1/2) * (4) * (3) A1 = 6$
 Rectangle 1:
 $A2 = (3) * (10) A2 = 30$
 Rectangle 2:
 $A3 = (4) * (10) A3 = 40$
 Rectangle 3:
 $A4 = (5) * (10) A4 = 50$
 Finally, the surface area is:
 $A = 2A1 + A2 + A3 + A4$
 Substituting values:
 $A = 2 * (6) + 30 + 40 + 50 A = 132$
 Answer:
 The surface area of a right triangle prism is:
 B. 132