Not every animation on the web is Flash but currently the
majority is. There exists simple GIF based animations as well as other
technologies for animation such as Silverlight and HTML5. Most believe HTML5
will eventually replace Flash.
Answer:
The answer is "Option B".
Explanation:
The main drawback of commercial security is, that the software may not protect digital technology against data mining, and they are not known to be the imperial tools, that's why the only option B is correct, and certain options are wrong, which can be explained as follows:
- In option A, It used to provide a sequence of instructions, which is used in security.
- In option C, It doesn't use in security, that's why it is wrong.
- Option D and Option E are wrong because in software there is no use of court and new software, it only upgrades the software.
Answer:
Table for Area codes are not missing;
See Attachment for area codes and major city I used
This program will be implemented using c++ programming language.
// Comments are used for explanatory purposes
// Program starts here
#include <iostream>
using namespace std;
int main( )
{
// Declare Variable area_code
int area_code;
// Prompt response from user
cout<<Enter your area code: ";
cin<<"area_code;
// Start switch statement
switch (area_code) {
// Major city Albany has 1 area code: 229...
case 229:
cout<<"Albany\n";
break;
// Major city Atlanta has 4 area codes: 404, 470 678 and 770
case 404:
case 470:
case 678:
case 770:
cout<<"Atlanta\n";
break;
//Major city Columbus has 2 area code:706 and 762...
case 706:
case 762:
cout<<"Columbus\n";
break;
//Major city Macon has 1 area code: 478...
case 478:
cout<<"Macon\n";
break;
//Major city Savannah has 1 area code: 912..
case 912:
cout<<"Savannah\n";
break;
default:
cout<<"Area code not recognized\n";
}
return 0;
}
// End of Program
The syntax used for the above program is; om
I think it is the model ET-2. Not quite sure.
Answer:
B. 1 6 3
Explanation:
Given function definition for calc:
void calc (int a, int& b)
{
int c;
c = a + 2;
a = a * 3;
b = c + a;
}
Function invocation:
x = 1;
y = 2;
z = 3;
calc(x, y);
cout << x << " " << y << " " << z << endl;
- Since x is passed by value, its value remains 1.
- y is passed by reference to the function calc(x,y);
Tracing the function execution:
c=3
a=3
b=c+a = 6;
But b actually corresponds to y. So y=6 after function call.
- Since z is not involved in function call, its value remain 3.
So output: 1 6 3