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Otrada [13]
3 years ago
12

You have three users who travel to four branch offices often and need to log on to the RODCs at these offices. The branch office

s are connected to the main office with slow WAN links. You don’t want domain controllers at the main office to authenticate these four users when they log on at the branch offices. What should you do that requires the least administrative effort yet adheres to best practices?
Computers and Technology
1 answer:
liberstina [14]3 years ago
8 0

Answer:

Configure Caching on RODCs using PRP.

Explanation

Read only domain controller is a domain controller that allows active directories for read only purposes. An administrator can setup RODCs for branches of a company and control the domain controller of the database server, updating the database which can be viewed as a read only partition in RODC.

Authenticating users in a RODC rely on the domain controller to forward the credentials to the read only domain controller. This can impose to high traffic on a slow WAN network link, especially when many users are trying to authenticate, resulting to high bandwidth.

To avoid this, credential caching by configuring password replication policy (PRP) on the RODC is vital.  

When PRP is configure on RODC, the user only get to authenticate once, then the user password is replicated and encrypted for subsequent use.

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3 years ago
Write the definition of a function divide that takes four arguments and returns no value . The first two arguments are of type i
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Answer:

#include <iostream>

using namespace std;

void divide(int numerator, int denominator, int *quotient, int *remainder)

{

*quotient = (int)(numerator / denominator);

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}

int main()

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divide(num, den, &quotient, &remainder);

 

return 0;

}

Explanation:

The exercise is for "Call by pointers". This technique is particularly useful when a variable needs to be changed by a function. In our case, the quotient and the remainder. The '&' is passing by address. Since the function is calling a pointer. We need to pass an address. This way, the function will alter the value at the address.

To sum up, in case we hadn't used pointers here, the quotient and remainder that we set to '0' would have remained zero because the function would've made copies of them, altered the copies and then DELETED the copies. When we pass by pointer, the computer goes inside the memory and changes it at the address. No new copies are made. And the value of the variable is updated.

Thanks! :)

8 0
3 years ago
Given the variables costOfBusRental and maxBusRiders of type int , write an expression corresponding to the cost per rider (assu
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Answer:

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Explanation:

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Explanation:

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