Simplify the expression 256b − b by combining like terms.
1 answer:
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Answer:
<em>P=760</em>
Step-by-step explanation:
Three of the coordinates of the square ABCD are A(-212,112) B(-212,-3) C(2,112). The image below shows the square is not ABCD but ABDC. In fact, this is not a square, as we'll prove later.
Note the x-coordinate of A and B are the same. It means this side is parallel to the y-axis. Also, the y-coordinate of A and C are the same, meaning this side is parallel to the x-axis. The missing point D should have the same x-coordinate as C and y-coordinate as B, i.e. D=(2,-3).
This shape has sides that are parallel to both axes.
To calculate the perimeter we find the length of two sides.
The distance from A to B is the difference between their y-axis:
w=112-(-3)=115
The distance from A to C is the difference between their x-axis:
l=2-(-212)=215
It's evident this is not a square but a rectangle. The perimeter is
P=2w+2l=330+430
P=760
<u>Given</u>:
Given that the triangle ABC has vertices A(-2,3), B(0,3) and C(-1,-1).
We need to determine the coordinates of the image after a reflection over the x - axis.
Let A'B'C' denote the coordinates of the triangle after a reflection over the x - axis.
<u>Coordinates of the point A':</u>
The general rule to reflect the coordinate across the x - axis is given by
Substituting the point A(-2,3), we get;
Thus, the coordinates of the point A' is (-2,-3)
<u>Coordinates of the point B':</u>
The general rule to reflect the coordinate across the x - axis is given by
Substituting the point B(0,3), we get;
Thus, the coordinates of the point B' is (0,-3)
<u>Coordinates of the point C':</u>
The general rule to reflect the coordinate across the x - axis is given by
Substituting the point C(-1,-1), we get;
Thus, the coordinates of the point C' is (-1,1)
Hence, the coordinates of the image after a reflection over the x - axis is A'(-2,-3), B(0,-3) and C(-1,1)