Answer:
A
Step-by-step explanation:
SO right off the bat it cannot be c, for they do definatly change.
Next, lets find out how much they change by.
The median would now be 120. Since adding 1 more number would make it just 120. Instead of it being 120+130/2.
This is a decrease of 5. Because we can just subtract normal number by new number: 125-120=5.
Now, the mean is already 500/4. This equals 125.
So lets add 0 to that. So now we must divide it by 1 more number, 4+1=5.
That is 500/5. This equals 100.
This is a decrease of 25. Because we can again subtrasct the normal number by the new number: 125-100=25
That is 5x more of a decrease than the mean.
SO it must be A, since the mean decreased more than the median.
Answer:
$15 - $11.50 = $3.50
$3.50 divided by .75 is 4.666
Which means the maximum number of toppings they can get is 4
Step-by-step explanation:
The dimensions of the enclosure that is most economical to construct are; x = 14.22 ft and y = 22.5 ft
<h3>How to maximize area?</h3>
Let the length of the rectangular area be x feet
Let the width of the area = y feet
Area of the rectangle = xy square feet
Or xy = 320 square feet
y = 320/x -----(1)
Cost to fence the three sides = $6 per foot
Therefore cost to fence one length and two width of the rectangular area
= 6(x + 2y)
Similarly cost to fence the fourth side = $13 per foot
So, the cost of the remaining length = 13x
Total cost to fence = 6(x + 2y) + 13x
Cost (C) = 6(x + 2y) + 13x
C = 6x + 12y + 13x
C = 19x + 12y
From equation (1),
C = 19x + 12(320/x)
C' = 19 - 3840/x²
At C' = 0, we have;
19 - 3840/x² = 0
19 = 3840/x²
19x² = 3840
x² = 3840/19
x = √(3840/19)
x = 14.22 ft
y = 320/14.22
y = 22.5 ft
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Step-by-step explanation:


30x = 9(2x+6)
30x = 18x+54
30x-18x = 54
12x = 54
x = 54/12
= 27/6