I believe that an insoluble solid that forms a chemical reaction is called a precipitate.
Precipitate is an insoluble solid that forms when two ionic compounds in solution are combined. Which means precipitation reaction is the creation of a solid from a solution, and when the reaction occurs in a liquid solution, the solid formed is called the precipitate. In fact the only method of forming insoluble salts is called precipitation or double decomposition of salts.
Answer:
The correct answer is - a. Fluorine is the leaving group in Sarin.
Explanation:
A leaving group is a group that leaves a complete negative charge in heterolytic cleavage when it separates out from the molecule. Sarine reacts with the active site of the enzyme acetylcholinesterase that is essential for nerve transmission.
In this given case, Sarin that is an acid fluoride and ester of methyl phosphonic acid, the fluorine atom is present is the one that leaves with a complete negative charge, therefore, fluorine is the leaving group in Sarin.
Thus, the first option is correct that Fluorine is the leaving group in Sarin.
<span>Which of the following gases would be most likely to experience ideal behavior at high pressures?
a. F2
b. Ne
c. C2H6
Yes. The answer is (b) Ne (Neon). This is because monoatomic gases such as neon do not experience </span><span>intermolecular attractions and thus most likely to be close to ideal gases behavior. Not only that, Neon is a noble gas and is unreactive. </span>
Answer:
The answer is 1.06g.
Explanation:
Analysis of question:
1. Identify the information in the question given.
- volume of HCl is 2 dm3
- pH of HCl is 2.0
2. What the question want?
- mass of Na2CO3 is ?(unknown)
- 3. Do calculation.
- 1st-Write a balanced chemical equation:
Na2CO3 + 2HCl (arrow) 2NaCl + H20 + CO2
- 2nd-Determine the molarity of HCl with the value of 2.0.
pH= -log[H+]
2.0= -log[H+]
log[H+]= -2.0
[H+]= 10 to the power of negative 2(10-2)
=0.01 mol dm-3
molarity of HCl is 0.01 mol dm-3
- 3rd-Find the number of moles of HCl
n=MV
=0.01 mol dm-3 × 2 dm3
=0.02 mol of HCl
- 4th-Find the second mol of it.
Based on the chemical equation,
2.0 mol of HCl reacts with 1.0 mol of Na2CO3
0.02 mol of HCl reacts with 0.01 mol of Na2CO3
<u>N</u><u>a</u>2CO3>a=<u>1</u><u> </u>mol
<u>2</u><u>H</u>Cl>b=<u>2</u><u> </u>mol
mass= number of mole × molar mass
g=0.01 × [2(23)+ 12+ 3(16)]
g=0.01 × 106
# =1.06 g.
