molar mass of methane CH4
= C + 4 H
= 12.0 + 4 x 1.008
= 12.0 + 4.032
= 16.042g/mol
7.31 x 10^25 molecules x <u> 1 mole CH4 </u> = 121.43 moles
6.02 x 10^23 CH4 molecules
121.43 moles CH4 are present.
Answer:
0.5133805136 moles.
Explanation:
1 gram of Al2(Co3)3 equals 0.0017112683785004 moles, we need the amount of moles produced in 300 grams of Al2(CO3)3, so we have to multiply 1 gram of Al2(CO3)3 times 300: 0.0017112683785004 x 300, in conclusion,
300 grams of Al2(Co3)3 equals 0.5133805136.
