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guajiro [1.7K]
2 years ago
12

How many kilometers are in a 7.21. mm

Chemistry
1 answer:
Readme [11.4K]2 years ago
6 0

Answer:

0.00000721 Kilometer

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What is the iupac name of the following compound? <br><br> 2,2-dimethyl-4-ethylheptane
Lady bird [3.3K]

Answer:

The IUPAC name of the compound has already been given which is 2,2-dimethyl-4-ethylheptane.

Explanation:

The IUPAC (International Union of Pure and Applied Chemistry) is an authority in chemistry that provides a guideline and standardized methods in the naming of compounds formed from the periodic table.

In order the give an IUPAC name to a compound, certain steps needs to be followed, these includes:

--> Identify the functional group in the compound as this will form the suffix. For example if the functional group is an alkane the suffix will be -ane.

--> Identify the longest carbon chain (it may not be a straight chain) that contains the functional group. This forms the prefix. Example: if the longest carbon chain is 7 carbon atoms then the prefix will be hept-

--> All the carbons of the longest chain should be numbered

--> Identify branched groups on the chain and name them according to the number of carbon atoms. They usually end with -yl.

--> Finally, combine the elements of the name is a single word.

The structural formula of the IUPAC compound can be found in the attached file for a better understanding. The branched groups are circled.

4 0
3 years ago
A sample of gas (1.9 mol) is in a flask at 21 °C and 697 mm Hg. The flask is opened and more gas is added to the flask. The new
Artyom0805 [142]

Answer: There are now 2.07 moles of gas in the flask.

Explanation:

PV=nRT

P= Pressure of the gas = 697 mmHg = 0.92 atm  (760 mmHg= 1 atm)

V= Volume of gas = volume of container = ?

n = number of moles = 1.9

T = Temperature of the gas = 21°C=(21+273)K= 294 K   (0°C = 273 K)

R= Value of gas constant = 0.0821 Latm\K mol

V=\frac{nRT}{P}=\frac{1.9\times 0.0821 \times 294}{0.92}=49.8L

When more gas is added to the flask. The new pressure is 775 mm Hg and the temperature is now 26 °C, but the volume remains same.Thus again using ideal gas equation to find number of moles.

PV=nRT

P= Pressure of the gas = 775 mmHg = 1.02 atm  (760 mmHg= 1 atm)

V= Volume of gas = volume of container = 49.8 L

n = number of moles = ?

T = Temperature of the gas = 26°C=(26+273)K= 299 K   (0°C = 273 K)

R= Value of gas constant = 0.0821 Latm\K mol

n=\frac{PV}{RT}=\frac{1.02\times 49.8}{0.0821\times 299}=2.07moles

Thus the now the container contains 2.07 moles.

6 0
2 years ago
A geological process (2 points)
densk [106]
They are all correct good job bud I hope it helps and good luck

4 0
3 years ago
Read 2 more answers
[Gradpoint-Question AK-4] Which equation represents a combustion reaction?
harina [27]
Would the answer be d wouldn't it

4 0
3 years ago
Read 2 more answers
What volume of 5.00 × 10-3 m hno3 is needed to titrate 80.00 ml of 5.00 × 10-3 m ca(oh)2 to the equivalence point? what volume o
Dimas [21]

Answer:

= 160 mL

Explanation:

The equation for the reaction is;

Ca(OH)2 + 2HNO3 -----> Ca(NO3)2 + 2H2O

Moles of Ca(OH)2 =  0.080 L x 5.00^-3 M

                              = 0.0004 moles

From the reaction; 2 moles of HNO3 reacts with 1 mole of Ca(OH)2

Thus; moles of HNO3 = 0.0004 Moles × 2

                                    = 0.0008 moles

Volume = moles/ molarity

Therefore; volume of HNO3= 0.0008 Moles/ 5 × 10^-3 M

                                              <u>= 0.16 L or 160 mL</u>

4 0
3 years ago
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