0.15*240=36 ml of alcohol in <span>240 ml of a 15% alcohol mixture
0.4x = </span>ml of alcohol in x ml of a 40% alcohol mixture
0.2(x+240)= ml of alcohol in (x+240) ml of a 20% alcohol mixture
0.15*240 + 0.4x = 0.2(x+240)
36+0.4x=0.2x+48
0.2x = 12
x=12/0.2=120/6=20 ml of a 40% alcohol mixture
Answer:
The answer to your question is 23.4 moles of Glucose
Explanation:
Data
moles of Oxygen = ?
moles of glucose = 3.9
-Balanced chemical reaction
1C₆H₁₂O₆ + 6O₂ ⇒ 6H₂O + 6CO₂
Process
1.- To solve this problem, use the coefficient of the balanced chemical equation, and use proportions and cross multiplication.
1 mol of C₆H₁₂O₆ -------------------- 6 moles of O₂
3.9 moles of C₆H₁₂O₆ ------------------ x
x = (3.9 x 6 ) / 1
x = 23.4 moles
2.- Conclusion
3.9 moles of glucose consume 23.4 moles of oxygen
Answer: Its a type of "network." A water supply network or water supply system is a system of engineered hydrologic and hydraulic components that provide water supply.
Explanation:<em> S</em><em>chools, factories, office buildings, and hospitals which have their own water systems.</em><em> Transient Non-Community Water System (TNCWS): A public water system that provides water in a place such as a gas station or campground where people do not remain for long periods of time</em>
There will be three moles of ions.
Because in an aqueous solution, HCl will break apart into <span>H<span>+ and Cl- ions.
</span></span>HCl -> <span>H+</span><span> + </span><span>C<span>l<span>−
</span></span></span>1.5 HCl -> 1.5 H+ + 1.5 Cl−<span>
So the aqueous solution will have 1.5 moles of hydrated hydrogen ions and 1.5 moles of hydrated chloride ions. So, a total of 3 moles of ions are present in the aqueous solution of 1.5 moles of HCl. </span>
