Answer:
The value of x = 20
Step-by-step explanation:
Given:
∠BOC = 3x - 15
∠COD = 2x + 5
Find:
The value of x
Computation:
⇔ ∠BOC + ∠COD = 90
⇔ 3x - 15 + 2x + 5 = 90
⇔ 5x - 10 = 900
⇔ 5x = 90 + 10
⇔ 5x = 100
⇔ x = 100 / 5
⇔ x = 20
The value of x = 20
Part 1:
6(x-5) = 5(x+5) (x = 55)
4y + 2 (-3 + 2y) = 1-y (x = 7/9)
Part 2:
4(a-6) = 8a - (4a-24) (No Solution)
4(2x-8) = 8(x-8) (No Solution)
2(3x-3) = -6x-6 (Identity (x = 0))
Answer:
the least integer for n is 2
Step-by-step explanation:
We are given;
f(x) = ln(1+x)
centered at x=0
Pn(0.2)
Error < 0.01
We will use the format;
[[Max(f^(n+1) (c))]/(n + 1)!] × 0.2^(n+1) < 0.01
So;
f(x) = ln(1+x)
First derivative: f'(x) = 1/(x + 1) < 0! = 1
2nd derivative: f"(x) = -1/(x + 1)² < 1! = 1
3rd derivative: f"'(x) = 2/(x + 1)³ < 2! = 2
4th derivative: f""(x) = -6/(x + 1)⁴ < 3! = 6
This follows that;
Max|f^(n+1) (c)| < n!
Thus, error is;
(n!/(n + 1)!) × 0.2^(n + 1) < 0.01
This gives;
(1/(n + 1)) × 0.2^(n + 1) < 0.01
Let's try n = 1
(1/(1 + 1)) × 0.2^(1 + 1) = 0.02
This is greater than 0.01 and so it will not work.
Let's try n = 2
(1/(2 + 1)) × 0.2^(2 + 1) = 0.00267
This is less than 0.01.
So,the least integer for n is 2
y-3=3(x+1)
opening the bracket
y-3=3x+3
y=3x+3+3
equation of the line in the form y=mx+c;
y=3x+6
therefore gradient=3
parallel lines have same gradient therefore gradient of the other line is 3
y--3/x-0=3
y+3=3(x-0)
y+3=3x-0
y=3x-3.
