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3 years ago

Write a program that Read first n lines of file

Computers and Technology

1 answer:

sergejj [24]3 years ago

7 0

Answer:

Python 2:

with open("datafile") as myfile:

head = [next(myfile) for x in xrange(N)]

print head

Python 3:

with open("datafile") as myfile:

head = [next(myfile) for x in range(N)]

print(head)

Both Python 2 & 3:

from itertools import islice

with open("datafile") as myfile:

head = list(islice(myfile, N))

print head

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If wire rope guard rails are used what must also be done?

zzz [600]

A Deceleration device.
A rope, wire rope, or strap with connectors at each end for connecting the 5 point body harness to a lifeline, or anchorage.

Look under OSHA Flashcards on Quizlet and..
OSHA: Fall Protection in Construction, Subpart M and just past that area in the document.

This is from that document on page 13 and 14:
Fall Restraint Systems: While fall restraint systems are not mentioned in Subpart M, OSHA recognizes a fall restraint system as a means of prevention. The system, if properly used, tethers a worker in a manner that will not allow a fall of any distance. This system is comprised of a body belt or body harness, an anchorage, connectors, and other necessary equipment. Other components typically include Photo: Skip Pennington OCCUPATIONAL SAFETY AND HEALTH ADMINISTRATION 1 4 a lanyard, a lifeline, and other devices. For a restraint system to work, the anchorage must be strong enough to prevent the worker from moving past the point where the system is fully extended, including an appropriate safety factor. *In a November 2, 1995 interpretation letter to Mr. Dennis Gilmore, OSHA suggested that, at a minimum, a fall restraint system must have the capacity to withstand at least 3,000 pounds or twice the maximum expected force that is needed to restrain the person from exposure to the fall hazard. In determining this force, consideration should be given to site-specific factors such as the force generated by a person (including his/her tools, equipment, and materials) walking, slipping, tripping, leaning, or sliding along the work surface.

8 0

3 years ago

Traceability of requirements is helpful in the followingexcept

larisa86 [58]

Answer: D) Identifying GUI's for a particular requirement

Explanation:

Traceability of requirements is helpful except identifying GUI's for a particular requirements as, traceability in project management describe the relationships between two or more element throughout in the development process and outline the relationship between the customer requirement by traceability matrix. And the requirement of traceability is so important because it creating a downstream flow of software and test cases in software requirement but not helpful in GUI identification.

6 0

3 years ago

Is Flip book drawings, frame by frame (need great drawing skills).

lyudmila [28]

I would say traditional animation

7 0

3 years ago

Write a complete Java program called Rooter that gets a positive integer called "start" from the user at the command line and th

Nataly_w [17]

Answer:

The program in Java is as follows:

import java.util.*;

import java.lang.Math;

public class Rooter{

public static void main(String[] args) {

Scanner input = new Scanner(System.in);

int start;

System.out.print("Start: ");

start = input.nextInt();

while(start<=0){

System.out.print("Number must be positive\nStart: ");

start = input.nextInt(); }

while(start>=0){

System.out.println(Math.sqrt(start));

start--; }

}

Explanation:

This declares start as integer

int start;

This prompts the user for input

System.out.print("Start: ");

This gets input for start

start = input.nextInt();

The following is repeated until the user input is valid i.e. positive

while(start<=0){

System.out.print("Number must be positive\nStart: ");

start = input.nextInt(); }

The following while loop prints the square root of each number till 0

while(start>=0){

System.out.println(Math.sqrt(start));

start--; }

4 0

2 years ago

Assignment Background Video games have become an outlet for artists to express their creative ideas and imaginations and a great

Sphinxa [80]

Answer:

Code

import csv

def open_file():

try:

fname=input("Enter the filename to open (xxx.yyy): ")

fp=open(fname,encoding='utf-8')

return fp

except FileNotFoundError:

print("File not found! Please Enter correct filename with extension")

return open_file()

def read_file(fp):

fields = []

rows = []

csvreader = list(csv.reader(fp))

# skiped 1 row because it contains field name

fields = csvreader[0]

D1={}

D2={}

D3={}

# accessing the data of csv file

for line in csvreader[1:]:

name = line[0].lower().strip()

platform = line[1].lower().strip()

if line[2]!='N/A':

year = int(line[2])

else:

year=line[2]

genre = line[3].lower().strip()

publisher = line[4].lower().strip()

na_sales = float(line[5])

eur_sales = float(line[6])

jpn_sales = float(line[7])

other_sales = float(line[8])

global_sales=(na_sales+eur_sales+jpn_sales+other_sales)*1000000

if name not in D1:

D1[name]=[]

D1[name].append((name, platform, year, genre, publisher,global_sales))

if genre not in D2:

D2[genre]=[]

D2[genre].append((genre, year, na_sales, eur_sales,jpn_sales, other_sales, global_sales))

if publisher not in D3:

D3[publisher]=[]

D3[publisher].append((publisher, name, year, na_sales,eur_sales, jpn_sales, other_sales, global_sales))

# sorting

temp={}

# sorting keys

for Keys in sorted (D1) :

ls=D1[Keys]

ls=sorted(ls,key=lambda x: x[-1]) # sorting values

temp[Keys]=ls

D1=temp.copy()

temp={}

# sorting keys

for Keys in sorted (D2) :

ls=D2[Keys]

ls=sorted(ls,key=lambda x: x[-1]) # sorting values

temp[Keys]=ls

D2=temp.copy()

temp={}

# sorting keys

for Keys in sorted (D3) :

ls=D3[Keys]

ls=sorted(ls,key=lambda x: x[-1]) # sorting values

temp[Keys]=ls

D3=temp.copy()

return D1,D2,D3

def main():

fp=open_file()

D1,D2,D3=read_file(fp)

# displaying the row_count in dictionaries

cnt=0

for d in D1:

cnt+=1

print(cnt)

print("\n\n=============================================\n\n")

cnt=0

for d in D2:

cnt+=1

print(cnt)

print("\n\n=============================================\n\n")

cnt=0

for d in D3:

cnt+=1

print(cnt)

print("\n\n=============================================\n\n")

if __name__=="__main__":

main()

Explanation:

see code and see output attached

7 0

3 years ago