Answer:
//here is the statement in java.
import java.util.*;
//class definition
class Solution
{
// main method of the class
public static void main (String[] args) throws java.lang.Exception
{
try{
// this statement will print the 3 2 1 Go! and go to newline
System.out.println("3 2 1 Go!");
}catch(Exception ex){
return;}
}
}
Explanation:
We can use "System.out.println()" to print the required output same as it required. After printing this, it will go to newline.
Output:
3 2 1 Go!
The answers are:
C
A
Hope it helps :)
Answer:
3 bits
Explanation:
Given a 4- way set associative cache that has 64 blocks of 16 words.
Therefore, the number of sets cache has:
Now,
Cache data size is 16kB
The number of cache blocks can be calculated as:
Now,
Total sets = 
Total sets = 
Now,
n = 6
For 15 bit address for the architecture, the bits in tag field is given by:
15 - (6 + 6) = 3 bits
Thus the tag field will have 3 bits
Answer:
Ans1.
double calc_a;
calc_a=Math.pow(3.0,2.0)+Math.sqrt(9);
Ans2.
double calc_b;
calc_b=((12.0/3.0)-(2.0*4.0));
Ans 3.
double calc_c;
calc_c=(Math.sqrt(16.0)*(7.0+9.0));
Ans 4.
double calc_d;
calc_d=Math.pow(7.0,2.0)/Math.sqrt(49.0);
Explanation:
The expressions are done with Java in answer above.
Answer:
I think mega frost dragon i d k
Explanation:
