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Schach [20]
3 years ago
13

Coding with Loops Worksheet

Computers and Technology
2 answers:
vovangra [49]3 years ago
7 0
Mmmmmmmmmmmmmmmmmmmmmmmm
Airida [17]3 years ago
4 0
Uhh this is giving me a headache
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You would like to search for information about storms but not tornadoes. What type of search strategy may be useful?
Helen [10]

Answer:One of the most interesting comments regards 'stemming': "Some of the search engines offering wildcard search also support what is called "stemming." That means they will find terms like "singing" even if you only enter "sing." This also means you may not need to use a wildcard symbol."

Explanation:

3 0
3 years ago
Read 2 more answers
If you add 111 and 0101 in 4-bit signed fields, is there a carry or overflow?
Ghella [55]

Answer: there is an overflow

Explanation:

Here using 4-bit signed fields to store the addition value.

0111 + 0101 = 1100

In above addition the MSB is reserved for sign.

If MSB is 0 means the number is positive.

If MSB is 1 means the number is negative.

The first number 0111 has MSB 0 means it is a positive number.

The second number 0101 has MSB 0 means it is also a positive number.

But after addition the result obtained is 1100 which MSB is 1 indicating the

result is negative number.

How can it be possible to add two positive numbers and get a negative number as result.

This type of situation is called overflow situation.

It is used for error detection purpose.

therefore there is an overflow

4 0
3 years ago
Help me with this…… please
Brums [2.3K]

Answer:

2. The texture is being use to look sturdy

3. some repetition are being repeated for example the blocks

4. No it because of the words

5. The words at the bottom

It my opinion so it might not be correct

8 0
2 years ago
What was the first general purpose, programmable, electronic computer?.
ryzh [129]

Answer:

ENIAC: first general-purpose electronic computer.

Explanation:

6 0
3 years ago
. Suppose an instruction takes 1/2 microsecond to execute (on the average), and a page fault takes 250 microseconds of processor
saul85 [17]

Answer:

a. 100.

b. 31500.

Explanation:

So, we are given the following data which is going to help in solving this particular question.

The time required to execute (on the average) = 1/2 microsecond , a page fault takes of processor time to handle = 250 microseconds and the disk time to read in the page = 10 milliseconds.

Thus, the time taken by the processor to handle the page fault = 250 microseconds / 1000 = 0.25 milliseconds.

The execution time = [ 1/2 microseconds ]/ 1000 = 0.0005 milliseconds.

The number of Pages sent in a second by the disc = 1000/10 milliseconds = 100.

Assuming U = 1.

Hence, the disc transfer time = [2/3 × 1 } + [ 1/3 × 0.25 milliseconds + 15 ] × 2.

=0.667 + 15.083.

= 15.75 millisecond.

Average number of instruction = 15.75/0.0005 = 31500.

8 0
3 years ago
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