1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
vlabodo [156]
3 years ago
13

The auto rental company rented 8,669 autos last month. This month it rented 3,742 more autos than it did last month. About how m

any autos did the company rent this month? Round each number to the nearest hundred. A. 5,000 B. 12,300 C. 12,400 D. 13,000
Mathematics
1 answer:
balandron [24]3 years ago
4 0
8,869 + 3,742 = 12,411. Rounded it's C., 12,400. Hope that helps!
You might be interested in
Vol=1348.79cm³. What's X? (Height)
ale4655 [162]
V = PI x r^2 x H

1348.79 = 3.14 x 5.5^2 x H

1348.79 = 94.985 x h
h = 1348.79 / 94.985
h = 14.2 cm  ( round answer if needed)


4 0
3 years ago
State the converse<br><br> Please helps asap
Paladinen [302]

Answer: True

Step-by-step explanation:

If x2 = 49, then x = 7. True; x = 7 if and only if x^2 = 49.

I hope this solves your problem! It was a little tricky but I tried.

please mark me Brainliest if your able

have a blessed day

7 0
2 years ago
Consider the initial value function y given by
Nuetrik [128]

Answer:

y(s) = \frac{5s-53}{s^{2} - 10s  + 26}

we will compare the denominator to the form (s-a)^{2} +\beta ^{2}

s^{2} -10s+26 = (s-a)^{2} +\beta ^{2} = s^{2} -2as +a^{2} +\beta ^{2}

comparing coefficients of terms in s

s^{2} : 1

s: -2a = -10

      a = -2/-10

      a = 1/5

constant: a^{2}+\beta ^{2} = 26

               (\frac{1}{5} )^{2} + \beta ^{2} = 26\\\\\beta^{2} = 26 - \frac{1}{10} \\\\\beta =\sqrt{26 - \frac{1}{10}} =5.09

hence the first answers are:

a = 1/5 = 0.2

β = 5.09

Given that y(s) = A(s-a)+B((s-a)^{2} +\beta ^{2} )

we insert the values of a and β

  \\5s-53 = A(s-0.2)+B((s-0.2)^{2} + 5.09^{2} )

to obtain the constants A and B we equate the numerators and we substituting s = 0.2 on both side to eliminate A

5(0.2)-53 = A(0.2-0.2) + B((0.2-0.2)²+5.09²)

-52 = B(26)

B = -52/26 = -2

to get A lets substitute s=0.4

5(0.4)-53 = A(0.4-0.2) + (-2)((0.4 - 0.2)²+5.09²)

-51 = 0.2A - 52.08

0.2A = -51 + 52.08

A = -1.08/0.2 = 5.4

<em>the constants are</em>

<em>a = 0.2</em>

<em>β = 5.09</em>

<em>A  = 5.4</em>

<em>B = -2</em>

<em></em>

Step-by-step explanation:

  1. since the denominator has a complex root we compare with the standard form s^{2} -10s+26 = (s-a)^{2} +\beta ^{2} = s^{2} -2as +a^{2} +\beta ^{2}
  2. Expand and compare coefficients to obtain the values of a and <em>β </em>as shown above
  3. substitute the values gotten into the function
  4. Now assume any value for 's' but the assumption should be guided to eliminate an unknown, just as we've use s=0.2 above to eliminate A
  5. after obtaining the first constant, substitute the value back into the function and obtain the second just as we've shown clearly above

Thanks...

3 0
2 years ago
12 - 3/4 (d + 16) = negative 5
Nutka1998 [239]

Answer: d=20/3

Step By Step:

Step 1, Simplify:

12-3/4(d+16)=-5

(-3/4)d+(12-12)=-5

(-3/4)d=-5

Step 2, Multiply each side by 4/(-3)

(4/-3)*(-3/4)d=(4/-3)*-5

d=20/3

8 0
3 years ago
Read 2 more answers
Erica is participating in a road race. The first part of the race is on a 5.2-mile-long straight road-oriented at an angle of 25
kap26 [50]

Answer:

6.31 mi

Step-by-step explanation:

The diagram below explains the solution better.

From the diagram,

C = starting point of the race.

A = end of the first part of the race.

B = end of the race.

Using Cosine rule, we can find the straight-line distance between the starting point and the end of the race.

Cosine rule states that:

a^2 = b^2 + c^2 - 2bc[cos(A)]

where A = angle A = <A

Given that

b = 5.2 miles

c = 2.0 miles

<A = 115° (from the diagram)

Hence,

a^2 = 5.2^2 + 2.0^2 - 2*5.2*2.0[cos(115)]\\\\a^2 = 27.04 + 4 - 20.8[cos(115)]\\\\a^2 = 31.04 + 8.79\\\\a^2 = 39.83\\\\a = \sqrt{39.83}\\ \\a = 6.31 mi

The straight-line distance between the starting point and the end of the race is 6.31 mi

4 0
3 years ago
Other questions:
  • Sue's Jewelry sold 20 necklaces for $25 each to a credit customer. The invoice included a 6% sales tax and payment terms of 2/10
    5·1 answer
  • PLZ HELP The slope of the graph of a direct variation function is 4. What is the equation of the function? y = 4 x + 1 y = 1/4 x
    7·2 answers
  • Please please help me! Here is a graph of y=7-x for values x from 0 to 7.
    11·1 answer
  • Find the percentage decrease if a players batting average dropped from 0.273 to 0.265 in one season.
    7·1 answer
  • Please help me please help me please help me
    7·1 answer
  • What is the volume of this?
    11·1 answer
  • PLEASE HELP
    9·2 answers
  • JJack, Jill, and Bill each carried a 48-fluid ounce bucket full of water down the hill. By the time they reached the bottom, Jac
    7·1 answer
  • 2x and 3x are like terms
    13·1 answer
  • If 5x+20=y,what is the value of x+4?
    5·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!