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vlabodo [156]
3 years ago
13

The auto rental company rented 8,669 autos last month. This month it rented 3,742 more autos than it did last month. About how m

any autos did the company rent this month? Round each number to the nearest hundred. A. 5,000 B. 12,300 C. 12,400 D. 13,000
Mathematics
1 answer:
balandron [24]3 years ago
4 0
8,869 + 3,742 = 12,411. Rounded it's C., 12,400. Hope that helps!
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Write the point-slope form of the equation of the line that passes through the point (-1, 5) and has a slope of -1.
Anastaziya [24]
Point slope form = y - y1 = m (x - x1)

y - 5 = -1 (x -(-1))
y - 5 = -1 (x+1)

Hope this helps :)
7 0
3 years ago
Prove that :-<br><br> Cos3A-cosA/sin3A-sinA+cos2A-cos4A/sin4A-sin2A=sinA/cos2Acos3A
ad-work [718]
\dfrac{\cos^3A-\cos A}{\sin^3A-\sin A}+\dfrac{\cos^2A-\cos^4A}{\sin^4A-\sin^2A}=\dfrac{\sin A}{\cos^2A\cos^3A}\\\\L_s=\dfrac{\cos A(\cos^2A-1)}{\sin A(\sin^2A-1)}+\dfrac{\cos^2A(1-\cos^2A)}{\sin^2A(\sin^2A-1)}\\\\=\dfrac{\cos A(-\sin^2A)}{\sin A(-\cos^2A)}+\dfrac{\cos^2A\sin^2A}{\sin^2A(-\cos^2A)}\\\\=\dfrac{\sin A}{\cos A}-1=\tan A-1

R_s=\dfrac{\sin A}{\cos A\cos^4A}=\dfrac{\sin A}{\cos A}\cdot\dfrac{1}{\cos^4A}=\tan A\cdot\dfrac{1}{\cos^4A}=\dfrac{\tan A}{\cos^4A}


\boxed{L_s\neq R_s}
8 0
3 years ago
What is the f(n) runtime of the following pseudocode: sum = 0 for A = N/2 downto 1 for B = 1 to 4N increment sum by B
nikitadnepr [17]

Answer:

f(N) = 2+ N/2 + 6N² units of time.

Step-by-step explanation:

Assigning 0 to the variable sum takes one unit of time.

Each time you increment sum by B, you need to call the value of sum, sum it to B and assign it to sum, which takes three units of time in total. You are repeating this process for each value of B which ranges from 1 to 4n and for each value of A which ranges from 1 to n/2. Opening the FOR takes also another unit of time, so, as a result, we have

f(N) 1 + 1 (open the FOR in A)+ N/2*(1 (open the FOR in B) + 4N*3) = 2+ N/2 + 6N² units of time. It has order complexity O(N²).

5 0
4 years ago
I need help ASAP please
Verdich [7]

Answer:

33

Step-by-step explanation:

first you set up the problem, supplementary angles equal 180 degrees so the equation should look like, 4x+x+15=180. then you solve from there by combining like terms and you should get x equal to 33

4 0
3 years ago
nicole is flying two kites. she has 104 feet of string out to one kite and 110 feet out to the other kite. the angle formed by t
Gnesinka [82]

Answer:

48.49 feet

Step-by-step explanation:

The diagrammatic sketch of the information provided in the question was attached in the image below.

From the image below, the distance between the two kites is denoted by (c) and can be determined by using the cosine angle rule which is expressed as:

c^2 = a^2 + b^2 -2ab cos \ C

where;

a = 110

b = 104

Cos C = 26°

Then;

c^2 = 110^2 + 104^2 -2(110)(104) cos \ 26 \\ \\  c^2 = 12100 + 10816- 22880 ( 0.8988) \\ \\  c^2 = 22916- 20564.544 \\ \\  c^2 = 2351.456 \\ \\  c= \sqrt{2351.456} \\ \\ \mathbf{ c = 48.49 \ feet}

4 0
3 years ago
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