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3 years ago

14

Find the value of variable x. If your answer is not an integer, write it in simplest radical form with the denominator rationali

zed.

1 answer:

Otrada [13]3 years ago

8 0

Answer:

the answer is 7

Step-by-step explanation:

angle 30°

x=14/2

x=7

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Leanne earned $400 and $550 in interest the last 2 years. How much interest must she earn this year so that her average earnings

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Answer:

850

Step-by-step explanation:

400+550+850=1800. 1800/3= 600

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3 years ago

Which numbers are the extremes of the proportion 3/4=6/8

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Step-by-step explanation:

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3 years ago

Read 2 more answers

If neither a nor b are equal to zero, which answer most accurately describes the product of (a + bi)(a - bi)?

Scrat [10]

Answer: the correct option is

(D) The imaginary part is zero.

Step-by-step explanation: Given that neither a nor b are equal to zero.

We are to select the correct statement that accurately describes the following product :

$P=(a+bi)(a-bi)~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(i)$

We will be using the following formula :

$(x+y)(x-y)=x^2-y^2.$

From product (i), we get

$P\\\\=(a+bi)(a-bi)\\\\=a^2-(bi)^2\\\\=a^2-b^2i^2\\\\=a^2-b^2\times (-1)~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~[\textup{since }i^2=-1]\\\\=a^2+b^2.$

So, there is no imaginary part in the given product.

Thus, the correct option is

(D) The imaginary part is zero.

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2 years ago

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How can I help you with your algebra

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3 years ago

A particle, initially at rest, moves along the x-axis such that its acceleration at time t > 0 is given by a(t) = 6cos(t). At

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a. By the fundamental theorem of calculus, the velocity function is

$v(t)=v(0)+\displaystyle\int_0^ta(u)\,\mathrm du$

The particle starts at rest, so $v(0)=0$ , and we have

$v(t)=\displaystyle\int_0^t6\cos u\,\mathrm du=6\sin u\bigg|_0^t=6\sin t$

Then the position function is

$x(t)=\displaystyle x(0)+\int_0^tv(u)\,\mathrm du$

with $x(0)=6$ , so

$x(t)=6+\displaystyle\int_0^t6\sin u\,\mathrm du=6-6\cos u\bigg|_0^t=12-6\cos t$

b. The particle is at rest whenever $v(t)=0$ ; this happens for

$6\sin t=0\implies \sin t=0\implies t=n\pi$

where $n$ is any integer.

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3 years ago