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4 years ago

14

Find the value of variable x. If your answer is not an integer, write it in simplest radical form with the denominator rationali

zed.

1 answer:

Otrada [13]4 years ago

8 0

Answer:

the answer is 7

Step-by-step explanation:

angle 30°

x=14/2

x=7

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Find the MAD {42, 50, 54, 38, 48). Round to nearest hundredth (two

makkiz [27]

Answer:

MAD is 5.12

Step-by-step explanation:

The following data were obtained from the question:

42, 50, 54, 38, 48

Next, we shall determine the mean of the data. This can be obtained as follow:

Mean = summation X / n

n is the number of the data.

Summation X = 42 + 50 + 54 + 38 + 48

Summation X = 232

n = 5

Mean = summation X / n

Mean = 232 / 5

Mean = 46.4

Therefore, the mean of the data is 46.4

Finally, we shall determine the mean absolute deviation (MAD) of the data as follow:

MAD = summation |mean – X| /n

MAD = (|(46.4 – 42) + (46.4 – 50) + (46.4 – 54) + (46.4 – 38) + (46.4 – 48|) /5

MAD = |4.4 + 3.6 + 7.6 + 8.4 + 1.6| /5

MAD = 25.6/5

MAD = 5.12

Therefore, the mean absolute deviation (MAD) is 5.12

5 0

3 years ago

Find the value of x of this question

mel-nik [20]

<h3><u>Let's</u><u> </u><u>understand</u><u> </u><u>the concept</u><u>:</u><u>-</u></h3>

Here angle B is 90°
So $\triangle ABC$ and $\triangle ABD$ Are right angled triangle
So we use Pythagoras thereon for solution

<h3><u>Required Answer</u><u>:</u><u>-</u></h3>

First in triangle ABC

perpendicular=p=8cm

Hypontenuse =h =10cm

We need to find base=b

According to Pythagoras thereon

${\boxed{\sf b^2=h^2-p^2}}$

Substitutethe values

$\longrightarrow$ $\sf b^2=10^2-p^2$

$\longrightarrow$ $\sf b={\sqrt {10^2-8^2}}$

$\longrightarrow$ $\sf b={\sqrt{100-64}}$

$\longrightarrow$ $\bf b={\sqrt {36}}$

$\longrightarrow$ $\sf b=6$

$\therefore$ $\overline{BC}=6cm$

BD=BC+CD

$\longrightarrow$ $BD=9+6$

$\longrightarrow$ $BD=15cm$

Now in $\triangle ABD$

Perpendicular=p=8cm

Base =b=15cm

We need to find Hypontenuse =AD(x)

According to Pythagoras thereon

${\boxed {\sf h^2=p^2+b^2}}$

Substitute the values

$\longrightarrow$ $\sf h^2=8^2+15^2$

$\longrightarrow$ $\sf h={\sqrt {8^2+15^2}}$

$\longrightarrow$ $\sf h={\sqrt {64+225}}$

$\longrightarrow$ $\sf h={\sqrt {289}}$

$\longrightarrow$ $\sf h=17cm$

$\therefore$ ${\underline{\boxed{\bf x=17cm}}}$

8 0

3 years ago

The vertices of a quadrilateral in the coordinate plane are known. How can the perimeter of the figure be found?

Vaselesa [24]

Answer: Maths

Step-by-step explanation:

4 0

3 years ago

I need help with All of those and im Done for tonight if you no only one just do it anyways and tell me

Andreyy89

#3)NO
#4)9 x 15 divided by 6
answer=$22.5
#5)25 x 5 divided by 1
answer=125miles
#6)2:20=1:10

3 0

3 years ago

Read 2 more answers

Which of the following does not preserve orientation.

Murljashka [212]

Translations move the pre-image horizontally or vertically, but retain its orientation.

Reflections reflect across axes, mirroring the pre-image. Reflections result in a change of orientation.

Dilations stretch or shrink the pre-image by a scale factor; they change the pre-image's size but retain the pre-image's orientation.

Rotations rotate around a center point, but don't change the direction of the shape (its orientation).

Answer:
g. reflections

8 0

3 years ago