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3 years ago

12

If f(x) = x³ + x, find

ula1" title="\frac{f(x+h)-f(x)}{h}, f\neq 0" alt="\frac{f(x+h)-f(x)}{h}, f\neq 0" align="absmiddle" class="latex-formula">.

1 answer:

Snowcat [4.5K]3 years ago

6 0

I think you are doing limits so this is what I did
and that's how I factored using the box method because it's easier to track distribution.

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Solve the word problem below using the steps given in the lesson above. Show your equation and each step you take to solve it.

maria [59]

Answer:

Let Tom's cards = x

Equation:

Neils Cards = x + 83 (Neil has 83 more cards)

x + 83 = 517 (Tom has 83 cards less than Neil)

x = 434

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3 years ago

Please help!! I really don't want to get this one question wrong and mess up my score :(

Elan Coil [88]

Answer:

12^9 is the correct answer to the question

Step-by-step explanation:

12^8+(-)8-(-)9=8-8+9=9

12^9

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3 years ago

Read 2 more answers

A single die is rolled twice. Find the probability of rolling an even number the first time and a number greater than 3 the seco

IceJOKER [234]

Events

• A: an even number is rolled in the first time

,

• B: a number greater than 3 is rolled the second time

The probability of rolling an even number is:

$\begin{gathered} P(A)=\frac{\text{ number of favorable outcomes}}{\text{ total possible outcomes}} \\ P(A)=\frac{3}{6} \\ P(A)=\frac{1}{2} \end{gathered}$

The probability of rolling a number greater than 3 is:

$\begin{gathered} P(B)=\frac{\text{ number of favorable outcomes}}{\text{ total possible outcomes}} \\ P(B)=\frac{3}{6} \\ P(B)=\frac{1}{2} \end{gathered}$

Events A and B are independent, then the probability of one happening after the other is:

$\begin{gathered} \text{ P(A and B) = }P(A)\cdot P(B) \\ \text{ Substituting with the values previously found:} \\ \text{ P(A and B) = }\frac{1}{2}\cdot\frac{1}{2} \\ \text{ P(A and B) = }\frac{1}{4} \end{gathered}$

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1 year ago

What is the simplest form of the expression? sqr root 6x^8y^9/ sqr root 5x^2y^4

expeople1 [14]

For slightly greater clarity, write this expression as

sqrt(6x^8y^9) 6x^8y^9
-------------------- This is equivalent to sqrt[ -------------------- ]
sqrt(5x^2y^4) 5x^2y^4

Reduce the quantity inside the square brackets, obtaining:

6*x^6*y^5
sqrt[ ---------------- ]
5

This simplifies as follows: sqrt[ 6/5 ] * [ x^3 * y^(5/2)

which can be simplified even further if you wish.

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3 years ago

Solve the inequality.<br><br><br> n + 6 < −4

adelina 88 [10]

Answer:

n < -10

Step-by-step explanation:

n + 6 < -4

n+ 6-6 < -4-6

n < -10

hope it's helpful ❤❤❤

THANK YOU.

5 0

3 years ago