From the identity:


the inverse of f is g such that f(g(x))=x,
we must find g(x), such that
![\frac{1}{cos[g(x)]}=x](https://tex.z-dn.net/?f=%20%5Cfrac%7B1%7D%7Bcos%5Bg%28x%29%5D%7D%3Dx%20)
thus,
![cos[g(x)]= \frac{1}{x}](https://tex.z-dn.net/?f=cos%5Bg%28x%29%5D%3D%20%5Cfrac%7B1%7D%7Bx%7D%20)

Answer: b. g(x)=cos^-1(1/x)
Answer:
More informally: The two's complement of an integer is exactly the same thing as its negation. ... It means "to find the negation of a number (i.e., its two's complement) you flip every bit then add 1"
N-3, n-2, n-1, n and the sum is
4n-6=198 add 6 to both sides
4n=204 divide both sides by 4
n=51
So the fourth number is 51.
You have

So, we have to compute g(7) and feed it as input to f(x). We have
